half-life of 25.3 s. How long does it take for the concentration of the reactant in the reaction to fall to one-eighth of its initial value? Express the time to three significant figures and include the appropriate units. and then part b is attached.. thank you, I hope someone can help me

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a.)  A first-order reaction has a half-life of 25.3 s. How long does it take for the concentration of the reactant in the reaction to fall to one-eighth of its initial value? Express the time to three significant figures and include the appropriate units.

and then part b is attached.. thank you, I hope someone can help me

Consider the following multistep reaction:
C + D = CD (fast)
CD + D →CD2 (slow)
CD2D→CD3 (fast)
C+ 3D →CD3 (overall)
Based on this mechanism, determine the rate law for the overall reaction.
Transcribed Image Text:Consider the following multistep reaction: C + D = CD (fast) CD + D →CD2 (slow) CD2D→CD3 (fast) C+ 3D →CD3 (overall) Based on this mechanism, determine the rate law for the overall reaction.
Expert Solution
Step 1

Given, 

Half life time (t1/2) = 25.3 s

1---1/2---1/4---1/8

So, to fall concentration 1/8 it requires 3 half life times

Now,

Time = 3 × 25.3 = 75.9 s

 

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