half-life of 25.3 s. How long does it take for the concentration of the reactant in the reaction to fall to one-eighth of its initial value? Express the time to three significant figures and include the appropriate units. and then part b is attached.. thank you, I hope someone can help me
half-life of 25.3 s. How long does it take for the concentration of the reactant in the reaction to fall to one-eighth of its initial value? Express the time to three significant figures and include the appropriate units. and then part b is attached.. thank you, I hope someone can help me
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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a.) A first-order reaction has a half-life of 25.3 s. How long does it take for the concentration of the reactant in the reaction to fall to one-eighth of its initial value? Express the time to three significant figures and include the appropriate units.
and then part b is attached.. thank you, I hope someone can help me

Transcribed Image Text:Consider the following multistep reaction:
C + D = CD (fast)
CD + D →CD2 (slow)
CD2D→CD3 (fast)
C+ 3D →CD3 (overall)
Based on this mechanism, determine the rate law for the overall reaction.
Expert Solution

Step 1
Given,
Half life time (t1/2) = 25.3 s
1---1/2---1/4---1/8
So, to fall concentration 1/8 it requires 3 half life times
Now,
Time = 3 × 25.3 = 75.9 s
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