-1 -1 At a certain temperature this reaction follows second-order kinetics with a rate constant of 4.91 M 'S : 2HI (g) → H, (g) +I, (g) Suppose a vessel contains HI at a concentration of 1.33M. Calculate the concentration of HI in the vessel 2.40 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. OM ?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
### Second-Order Reaction Kinetics Educational Module

#### Reaction Overview
At a certain temperature, this reaction follows second-order kinetics with a rate constant of \(4.91 \, M^{-1} \cdot s^{-1}\):

\[ 2\text{HI (g)} \rightarrow \text{H}_2 \text{(g)} + \text{I}_2 \text{(g)} \]

#### Problem Statement
Suppose a vessel contains HI at a concentration of \(1.33 \, M\). Calculate the concentration of HI in the vessel \(2.40\) seconds later. You may assume no other reaction is important.

Round your answer to 2 significant digits.

#### Inputs and Interface
- **Initial Concentration (\( [HI]_0 \)**): \(1.33 \, M\)
- **Time (t): 2.40 \, \text{s}**

- **Rate Constant (k):** \(4.91 \, M^{-1} \cdot s^{-1}\)

- **Required Output:** Concentration of HI \( [HI] \, \text{(M)} \) after \(2.40 \, \text{s}\)

#### Solving the Problem
To calculate the concentration of HI after a given time period for a second-order reaction, the integrated rate law for second-order kinetics is used:

\[
\frac{1}{[HI]_t} = \frac{1}{[HI]_0} + kt
\]

Where:
- \([HI]_t\) is the concentration of HI at time t
- \([HI]_0\) is the initial concentration of HI
- \(k\) is the rate constant
- \(t\) is the elapsed time

Rearranging for \([HI]_t\):

\[
[HI]_t = \frac{1}{ \frac{1}{[HI]_0} + kt }
\]

Substituting the given values:

\[
[HI]_t = \frac{1}{ \frac{1}{1.33} + (4.91 \times 2.40) }
\]

Perform the calculations to find the concentration of HI:

\[
[HI]_t = \frac{1}{ 0.7519 + 11.784 } = \frac{1}{ 12.5359 } \approx 0.079
Transcribed Image Text:### Second-Order Reaction Kinetics Educational Module #### Reaction Overview At a certain temperature, this reaction follows second-order kinetics with a rate constant of \(4.91 \, M^{-1} \cdot s^{-1}\): \[ 2\text{HI (g)} \rightarrow \text{H}_2 \text{(g)} + \text{I}_2 \text{(g)} \] #### Problem Statement Suppose a vessel contains HI at a concentration of \(1.33 \, M\). Calculate the concentration of HI in the vessel \(2.40\) seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits. #### Inputs and Interface - **Initial Concentration (\( [HI]_0 \)**): \(1.33 \, M\) - **Time (t): 2.40 \, \text{s}** - **Rate Constant (k):** \(4.91 \, M^{-1} \cdot s^{-1}\) - **Required Output:** Concentration of HI \( [HI] \, \text{(M)} \) after \(2.40 \, \text{s}\) #### Solving the Problem To calculate the concentration of HI after a given time period for a second-order reaction, the integrated rate law for second-order kinetics is used: \[ \frac{1}{[HI]_t} = \frac{1}{[HI]_0} + kt \] Where: - \([HI]_t\) is the concentration of HI at time t - \([HI]_0\) is the initial concentration of HI - \(k\) is the rate constant - \(t\) is the elapsed time Rearranging for \([HI]_t\): \[ [HI]_t = \frac{1}{ \frac{1}{[HI]_0} + kt } \] Substituting the given values: \[ [HI]_t = \frac{1}{ \frac{1}{1.33} + (4.91 \times 2.40) } \] Perform the calculations to find the concentration of HI: \[ [HI]_t = \frac{1}{ 0.7519 + 11.784 } = \frac{1}{ 12.5359 } \approx 0.079
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Rate Laws
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY