A poll of 60 women and 40 men finds that 80% of the women and 70% of the men like a certain movie. Assume these are each simple random samples of the people of their gender in a large town. Find a 95% confidence interval for the difference between the proportion of women in this town and the proportion of men who like the movie. O -0.074, 0.274] O [0.429, 0.471] O [0.112, 0.164] O (-0.070, 0.183] O [0.359, 0.412] (-0.058, 0.042]

A poll of 60 women and 40 men finds that 80% of the women and 70% of the men like a certain movie. Assume these are each simple random samples of the people of their gender in a large town. Find a 95% confidence interval for the difference between the proportion of women in this town and the proportion of men who like the movie. O -0.074, 0.274] O [0.429, 0.471] O [0.112, 0.164] O (-0.070, 0.183] O [0.359, 0.412] (-0.058, 0.042]

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

From a sack of fruit containing 3 oranges, 2 apples, and 3 bananas, a random sample of 5 pieces of fruit is selected. If X is the number of oranges and Y is the number of apples in the sample, the joint probability distribution of X and Y is given by the accompanying function. Determine the correlation coefficient between X and Y.
A sunscreen company is attempting to improve upon their formula so that it lasts in water longer. They have 4 lead scientists who each came up with a different formulas. In order to see if there is a difference in the time the sunscreen lasts the CEO collects a random sample of each of the four sunscreens the data is shown below. Test the claim that at least one sunscreen has a different lifespan in water at a 0.05 level of significance. Sunscreen A Sunscreen B Sunscreen C Sunscreen D 43 66 64 49 90 80 51 74 40 57 44 83 87 74 63 43 43 31 49 84 58 57 64 68 The hypotheses for this ANOVA test would be: Η 0: μ Αμ Bμσ μ p HA : At least one mean is different. (claim) α 0.05 Complete the ANOVA table below: (round answers to 3 decimal places) df MS F p-value Between 368.5 3 122.8333 0.410311 0.747339 Within 5987.333 20 299.8667 The decision of the test is to: reject Ho • do not reject Ho
The following is used for questions 25, 26, and 27. In a random sample of 200 adults, 54 say they are in favor of outlawing cigarettes. Let p be the proportion of all adults who are in favor of outlawing cigarettes. One is interested for the following hypotheses: Ho : p = 0.23 versus H. : p #0.23. 25. The standardized test statistics is about (a) -1.34. (b) -1.27 (c) 1.27 (d) 0.27 (e) 1.34 26. The P-value of this test is (a) 0.0901 (b) 0.1802 (c) 0.9099 (d) 0.8980 (e) 1.8198 27. With the significance level a of 0.01, find the rejection region.
A sunscreen company is attempting to improve upon their formula so that it lasts in water longer. They have 4 lead scientists who each came up with a different formulas. In order to see if there is a difference in the time the sunscreen lasts the CEO collects a random sample of each of the four sunscreens the data is shown below. Test the claim that at least one sunscreen has a different lifespan in water at a 0.05 level of significance. Sunscreen A Sunscreen B Sunscreen C Sunscreen D 81 75 52 79 77 34 40 87 64 39 32 72 47 43 61 58 57 47 48 46 80 43 38 63 The hypotheses for this ANOVA test would be: H0:μA=μB=μC=μDH0:μA=μB=μC=μD HA:HA: At least one mean is different. (claim) α=0.05α=0.05 Complete the ANOVA table below: (round answers to 3 decimal places) SS df MS F p-value Between Within The decision of the test is to: reject H0H0 do not reject H0H0 The final conclusion is: There is not enough evidence to reject the claim that…
A manager of a product sales group believes the number of sales made by an employee (Y) depends on how many years that employee has been with the company (X1) and how he/she scored on a business aptitude test (X2). A random sample of 8 employees provides the following (refer Table 4): TABLE 4: Employee Y X1 X2 1 100 10 7 2 90 3 10 3 80 8 9 4 70 5 4 5 60 5 8 6 50 7 5 7 40 1 4 8 30 1 1 a) Run a regression analysis based on the data in Table 4 using Mic. Office EXCEL. Based on the output, propose a regression equation that can be used to predict the number of sales by an employee. (b) Interpret the coefficient value of each independent variable in the constructed model. (c) Is each independent variable sharing a significant linear relationship with the dependent variable? Verify at 0.05 level of significance. Make your conclusion based on the p-value in the EXCEL output.
A random sample of n1 = 16 communities in western Kansas gave the following information for people under 25 years of age. x1: Rate of hay fever per 1000 population for people under 25 100 92 122 127 93 123 112 93 125 95 125 117 97 122 127 88 A random sample of n2 = 14 regions in western Kansas gave the following information for people over 50 years old. x2: Rate of hay fever per 1000 population for people over 50 97 108 100 96 110 88 110 79 115 100 89 114 85 96 Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1 = s1 = x2 = s2 = What is the value of the sample test statistic?
A random sample of n1 = 16 communities in western Kansas gave the following information for people under 25 years of age. x1: Rate of hay fever per 1000 population for people under 25 100 92 121 129 93 123 112 93 125 95 125 117 97 122 127 88 A random sample of n2 = 14 regions in western Kansas gave the following information for people over 50 years old. x2: Rate of hay fever per 1000 population for people over 50 93 108 103 98 112 88 110 79 115 100 89 114 85 96 (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1 = s1 = x2 = s2 = What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)A random sample of n1 = 16 communities in western Kansas gave the following information for people under 25 years of age. x1: Rate of hay fever per 1000 population for people under 25 100 92 121 129 93 123 112 93 125 95 125 117 97 122 127 88 A…
In a survey of 500 drivers from the South, 408 wear a seat belt. In a survey of 370 drivers from the Northeast, 288 wear a seat belt. At a = 0.07, can you support the claim that the proportion of drivers who wear seat belts is greater in the South than in the Northeast? Assume the random samples are independent. Complete parts (a) through (e). (a) Identify the claim and state H, and H. The claim is "the proportion of drivers who wear seat belts in the South is greater than in the Northeast." Let p, represent the population proportion for the South, and p, represent the population proportion for the Northeast. State Ho and H Choose the correct answer below. O A. Ho: P1> P2 Ha: P, SP2 O B. Ho: P1 = P2 H,: P, *P2 OC. Ho: P1 *P2 H P, = P2 YE. Ho: P1 SP2 H P, > P2 OF. Ho: P1 2P2 H,: P, OA. 1.48 Oc. (c) Find the standardized test statistic. z= (Round to two decimal places as needed.)
(iii) Find (or estimate) the P-value. OP-value> 0.250 O 0.125 < P-value < 0.250 O 0.050 < P-value < 0.125 O 0.025 < P-value < 0.050 O 0.005 < P-value < 0.025 O P-value < 0.005 Sketch the sampling distribution and show the area corresponding to the P-value. ^^^^ (iv) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a? O At the a= 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. O At the a O At the a= O At the a 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. (v) Interpret your conclusion in the context of the application. O Fail to reject the null hypothesis, there is insufficient evidence…
Executives of a supermarket chain are Interested in the amount of time that customers spend in the stores during shopping trips. The mean shopping time, p, spent by customers at the supermarkets has been reported to be 35 minutes, but executives hire a statistical consultant and ask her to determine whether it can be concluded that u is different from 35 minutes. To perform her statistical test, the consultant collects a random sample of shopping times at the supermarkets. She computes the mean of these times to be 39 minutes and the standard deviation of the times to be 12 minutes. Based on this information, answer the questions below. What are the null hypothesis (Ho) and the alternative hypothesis (H) that should be used for the test? Ho: H is (? H1: u is (? + ? In the context of this test, what is a Type I error? :) the hypothesis that u is + when, in fact, u is A Type I error is ? Suppese that the consultant-deeldes net te reject the null hypothesis. What sort of error might she…
A random selection of volunteers at a research institute has been exposed to a weak flu virus. After the volunteers began to have flu symptoms, 10 of them were given multivitamin tablets daily that contained 1 gram of vitamin C and 3 grams of various other vitamins and minerals. The remaining 10 volunteers were given tablets containing 4 grams of vitamin C only. For each individual, the length of time taken to recover from the flu was recorded. At the end of the experiment the following data were obtained. Days to recover from flu Treated with 4.0, 7.9, 6.1, 2.9, 4.0, 4.0, 4.5, 6.4, 5.6, 2.3 multivitamin Treated with 4.0, 6.6, 8.5, 3.2, 4.8, 2.6, 3.4, 3.2, 7.6, 7.7 vitamin C Send data to calculator v Suppose that it is known that the population standard deviation of recovery time from the flu is 1.8 days when treated with multivitamins and that the population standard deviation of recovery time from the flu is 1.5 days when treated with vitamin C tablets. Suppose also that both…
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.0 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.3 4.5 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. (i) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to three decimal places.) x1 = s1 = x2 = s2 = (ii) Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use α = 0.01.(a) What is the level of significance? What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)