A patient cannot clearly see any object that lies closer than 31.0 cm to his left eye. However, the patient wishes to see objects as close as 20.0 cm with that eye. The patientrequests eyeglasses to address the problem.(a) Is the patient nearsighted or farsighted?O nearsightedⒸfarsighted✔(b) If the eyeglass lens lies 2.06 cm in front of the patient's eye, what is the minimum distance p (in cm) separating the lens from an object he wants to see? (Give youranswer to at least three significant digits.)17.9cm(c) The patient is unable to focus clearly on anything closer than 31.0 cm to his eye (this being the patient's near point). The image formed by the eyeglass lens musttherefore be 31.0 cm from the eye. How far, then, (in cm) would the image lie from the lens? (Give your answer to at least three significant digits.)28.9✓ cm(d) The image lies on the same side of the lens as the original object. Is the image real or virtual, and is its position a positive or negative? (Select all that apply. Note thatyour answer to the previous part is the absolute value of the image position, or lql.)Oreal image✓ virtual imagedistance is positive✔distance is negative(e) What is the lens focal length f (in cm)?cm(f) Compute the power (in diopters) that corresponds to this focal length.diopters9 =f =P =(g) Suppose now that the patient desires contact lenses instead of eyeglasses. What values of p, q, f, and power P would describe the correct contact lens for the eyeunder discussion? (Enter p and q to at least three significant digits. Enter p, q, and fin cm. Enter P in diopters.)P =cmcmcmdiopters

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