An optometrist needs to prescribe corrective lenses for a person whose near point is q = 58.8 cm. If the patient is to see objects clearly at a distance of p = 25.0 cm, calculate the following. (Neglect the distance from the lens to the eye.) (a) focal length (in cm) of the appropriate corrective lens cm (b) power (in diopters) of the appropriate corrective lens diopters
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- (a) What is the power and the focal length of the eye when viewing an object 50.0 cm away? (b) Calculate the power and the focal length of the eye when viewing an object 3.00 m away.Use the worked example above to help you solve this problem. The near point of a patients eye is 50.0 cm. (a) What focal length must a corrective lens have to enable the eye to see clearly an object 29.9 cm away? Neglect the eye-lens distance. 69.0 x cm (b) What is the power of this lens? +1.45 X diopters (c) Repeat part (b), taking into account the fact that, for typical eyeglasses, the corrective lens is 2.00 cm in front of the eye. +2.21 X dioptersAn individual is nearsighted; his near point is 17.0 cm and his far point is 49.0 cm. (a) What lens power is needed to correct his nearsightedness? diopters(b) When the lenses are in use, what is this person's near point?
- A prescription for an eyeglass lens calls for +3.50 diopters. The lensmaker grinds the lens from a “blank” withand convex front surface of radius of curvature n=1.56of 30.0 cm. What should be the radius of curvature of theother surface?In sports photography, one often needs a long telephoto lens with a large aperture. As a designer, you will work with engineers to design some new lens.“ (i) Suppose you want to have an 500mm lens with aperture f/4. Calculate the required iris diameter. Round your answer to the nearest integer and state its unit. “ |(ii) Suppose you want to have a 700mm lens with a surface area of 12271.8463mm². Calculate the f-number. Correct your answer to 2_decimal places.Needs Complete solution with 100 % accuracy.
- Homework 12 Problem 10: Two lenses are mounted d = 27 cm apart on an optical bench. The focal length of the first lens is f1 = 5.1 cm and that of the second lens is f2 = 4.4 cm. An object of height ho = 3.5 cm is placed at a distance of do = 21 cm in front of the first lens. Part (a) Ignoring the second lens for now, at what distance, in centimeters, behind the first lens is the object’s image formed by that lens? di = ______ Part (b) Calculate the magnification of that image, including its sign. m = ______ Part (c) Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D = ______Problem 12: A student wears eyeglasses of power P = -3.75 diopter to correct nearsightedness. The glasses are designed to be worn d = 1.3 cm in front of the eye. Part (a) Input an expression for the far point the student can see without correction, do. Part (b) Numerically, what is the distance in meters?Please Asap