3) Your object distance is 240 cm, and your focal length is 80 cm. Use the thin-lens equation to predict the theoretical location of the image \( d_{i,theo} \). Show your work below.\[ d_{i,theo} = \underline{\hspace{10cm}} \]4) Use the magnification equation to predict the theoretical magnification of the image. Show your work below.\[ m_{theo} = \underline{\hspace{10cm}} \] This image is a diagram illustrating the behavior of light rays through a concave lens. The setup includes several components:1. **Object 1**: Represented by an upward arrow placed at the 20 cm mark on a vertical ruler.2. **Concave Lens**: Situated in the center of the horizontal plane, focusing the light rays.3. **Light Rays**: Three rays are depicted passing through the lens from Object 1. - **Marginal Rays**: Shown diverging after passing through the lens. - **Principal Ray**: Illustrated with a straight blue line intersecting the optical axis at the lens's center.4. **Rulers**: Horizontal and vertical rulers are used to measure distances and positions in centimeters.5. **Focal Points (F)**: Indicated on the horizontal ruler, showing the theoretical focal length of the concave lens.6. **Controls**: - **Radius of Curvature**: Adjustable parameter set to 80 cm. - **Index of Refraction**: Adjustable, set to 1.50. - **Diameter**: Adjustable diameter of the lens set to 80 cm. - Options for displaying various features like focal points, virtual images, and labels are checked.This diagram is designed to help visualize how a concave lens causes light rays to diverge, affecting the formation and position of images, which is crucial in understanding lens behavior in optical systems.

Answered: Image /qna-images/answer/3f632057-5337-4448-928b-c29ee05b524d.jpg

3) Your object distance is 240 cm, and your focal length is 80 cm. Use the thin-lens equation to predict the theoretical location of the image di,theo. Show your work below. di, theo 4) Use the magnification equation to predict the theoretical magnification of the image. Show your work below. mtheo =

3) Your object distance is 240 cm, and your focal length is 80 cm. Use the thin-lens equation to predict the theoretical location of the image di,theo. Show your work below. di, theo 4) Use the magnification equation to predict the theoretical magnification of the image. Show your work below. mtheo =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.

Question

3) Your object distance is 240 cm, and your focal length is 80 cm. Use the thin-lens equation to predict the theoretical location of the image \( d_{i,theo} \). Show your work below.

\[ d_{i,theo} = \underline{\hspace{10cm}} \]

4) Use the magnification equation to predict the theoretical magnification of the image. Show your work below.

\[ m_{theo} = \underline{\hspace{10cm}} \]

This image is a diagram illustrating the behavior of light rays through a concave lens. The setup includes several components:

1. **Object 1**: Represented by an upward arrow placed at the 20 cm mark on a vertical ruler.

2. **Concave Lens**: Situated in the center of the horizontal plane, focusing the light rays.

3. **Light Rays**: Three rays are depicted passing through the lens from Object 1.
- **Marginal Rays**: Shown diverging after passing through the lens.
- **Principal Ray**: Illustrated with a straight blue line intersecting the optical axis at the lens's center.

4. **Rulers**: Horizontal and vertical rulers are used to measure distances and positions in centimeters.

5. **Focal Points (F)**: Indicated on the horizontal ruler, showing the theoretical focal length of the concave lens.

6. **Controls**:
- **Radius of Curvature**: Adjustable parameter set to 80 cm.
- **Index of Refraction**: Adjustable, set to 1.50.
- **Diameter**: Adjustable diameter of the lens set to 80 cm.
- Options for displaying various features like focal points, virtual images, and labels are checked.

This diagram is designed to help visualize how a concave lens causes light rays to diverge, affecting the formation and position of images, which is crucial in understanding lens behavior in optical systems.

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Use the information from the lecture on the rules for ray tracing to complete the ray tracing for the different situations below. This part is graded on completeness so just try it out even if you feel it is wrong. Notice it is important to not get confused between the rules for lenses and mirrors. 1. Consider a concave mirror. An object is placed at various object distances from the mirror. For each case, use ray tracing to determine the following characteristics of the image: * is it real or virtual? n is it upright or inverted? n is it smaller or bigger than the object (or the same size)? n where is the image located? (approximate location – does not have to be exact) Assume a concave mirror with a focal length of f=5cm. Make sure to use a ruler and follow the ray-tracing rules. Draw a diagram for each of the following cases: (a) object is at f/2 (b) object is at f (c) object is at 3f/2 (halfway between center of curvature and focal length) (d) object is at 2f (exactly at center of…
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