A person decides to use an old pair of eyeglasses to make some optical instruments. He knows that the near point in his left eye is 48.0 cm and the near point in his right eye is 108cm.(a) What is the maximum angular magnification he can produce in a telescope?xYour incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation(b) If he places the lenses 10.0 cm apart, what is the maximum overall magnification he can produce in a microscope? Hint: Go back to basics and use the thin-lens equationto solve part (b).Consider at what distance from the eye the eyepiece must form its image to be viewed comfortably. Then using the focal lengths calculated in part (a) for each lensarrangement, calculate the magnification and location of the image formed by the eyepiece. Then use that image as the object for the second lens in order to find its imagelocation and magnification.Need Help?Read itSubmit AnswerMaster

The least distance that an eye can perceive is 25cm in adults.

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A person decides to use an old pair of eyeglasses to make some optical instruments. He knows that the near point in his left eye is 58.0 cm and the near point in his right eye is 106 cm. (a) What is the maximum angular magnification he can produce in a telescope? (b) If he places the lenses 10.0 cm apart, what is the maximum overall magnification he can produce in a microscope? Hint: Go back to basics and use the thin-lens equation to solve part (b).
The lens-to-retina distance of a woman is 2.04 cm, and the relaxed power of her eye is 53.8 D. (a) What is her far point?How is the refracting power of a person's eye for distant vision related to their far point and lens-to-retina distance? m(b) What eyeglass power will allow her to see distant objects clearly, if her glasses are 1.80 cm from her eyes?D
On H % 5 Stock of Data 6 Solution 6. For a converging lens the object is 12 cm from the lens and the image is 12 cm from the lens on the opposite side. What the magnification of the image? Physics-Problem Solving Entries Y Sanity Check Key Idea Stock of Data Solution Accessibility: Good to go Q Search Sanity Check & 7 U F8 * 8 1 8 F9 ( 9 F10 O F11 P O F12 PrtSc OFC
Your camera’s zoom lens has an adjustable focal length ranging from 55 to 150 mm. Part (a) What is the maximum power of the lens, Pmax, in diopters? Part (b) What is the minimum power of the lens, Pmin, in diopters?
A patient cannot clearly see any object that lies closer than 32.0 cm to her right eye. However, the patient wishes to see objects as close as 20.0 cm with that eye. The patient requests eyeglasses to address the problem. (a) Is the patient nearsighted or farsighted? nearsightedfarsighted (b) If the eyeglass lens lies 2.10 cm in front of the patient's eye, what is the minimum distance p (in cm) separating the lens from an object she wants to see? (Give your answer to at least three significant digits.) cm (c) The patient is unable to focus clearly on anything closer than 32.0 cm to her eye (this being the patient's near point). The image formed by the eyeglass lens must therefore be 32.0 cm from the eye. How far, then, (in cm) would the image lie from the lens? (Give your answer to at least three significant digits.) cm (d) The image lies on the same side of the lens as the original object. Is the image real or virtual, and is its position q positive or…
is: On H 5 T Key Idea Stock of Data Solution Sanity Check 7. For a converging lens with a focal length of 12 cm viewing an object at a distance of 6 cm. Where is the image located? Physics-Problem Solving Entries Key Idea Stock of Data Solution Sanity Check Accessibility: Good to go Q Search F6 F7 & 6 7 Y U F8 * 0 8 8 11 1 F9 F10 9 O O O F11 ) 0 P F12 H Prt
let aperture stop == radius of lens == object height
A near-sighted man can only focus on distances of dfar = 5.66 m or closer. What power lenses does he need in his glasses for distance vision? Your answer should be in diopters (m-1).
To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it. The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea whenp = 28.0 cm and M = 0.0140.