A particular fruit's weights are normally distributed, with a mean of 347 grams and a standard deviation of 25 grams. If you pick one fruit at random, what is the probability that it will weigh between 366 grams and 379 grams. Round your answer to three decimal places.
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A particular fruit's weights are
If you pick one fruit at random, what is the probability that it will weigh between 366 grams and 379 grams. Round your answer to three decimal places.
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- A scientist found that the lengths of a certain population of snakes can be reasonably described using a normal distribution with a mean of 42 cm and a standard deviation of 2 cm. If the scientist collected a sample of 89 snakes, how many of the snakes would be expected to have a length less than 40 cm? A 14 30 C 60 D 74The local ranger station tracked and tagged 2,844 adult female black bears in a national park. A random sample of 9 adult female black bears from those tagged had an average body weight of 203 pounds with standard deviation 25 pounds. Which of the following is a point estimate for the population mean weight of all female black bears that are tagged? A 9. C 25 D 203 2,844A couple plans to have 5 children. Assume that girl and boy births are equally likely. Find the mean number of girls in 5 births. Round your answer to one decimal place, if needed.
- Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.For a certain group of individuals, the average heart rate is 74 beats per minute. Assume the variable is normally distributed and the standard deviation is 4 beats per minute. If a subject is selected at random, find the probability that the person has the following heart rate. Use a graphing calculator. Round the answers to four decimal places. Less than 78 beats per minute =In an Algebra class, the scores on a test are normally distributed. The middle 68% of the scores fall between 71 and 83. What are the mean and standard deviation for this data?
- Students in a class took a test whose results were normally distributed. The mean score was an 81 and the standard deviation was 4.5. What score is at the 83rd percentile (round to the nearest whole number.) a.84 b.83 c.85 d.86Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Pa1, the 91st percentile. This is the temperature reading separating the bottom 91% from the top 9%. Click to view page 1 of the table Click to view page 2 of the table. Which graph represents Pa,? Choose the correct graph below. OD. Oc. OB. OA. Ay The temperature for P91 is approximately . (Round to two decimal places as needed.) XLSX Click to select vour answerls). 33283.xls Exit Honorlock 22 MacBook Air 吕0 000 000 F4 F3 F6 F7 F8 F9 FIC #3 2$ * 3 4 5 6 7 8 E R Y UAssume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation a = 15. Find the probability that a randomly selected adult has an IQ between 91 and 119. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ between 91 and 119 is. (Type an integer or decimal rounded to four decimal places as needed.) Enter your answer in the answer box. MacBook Air esc 888 %23 & 2 3 4 5 6 7 8 Q E R T Y tab P A D G H caps lock K V в N M > ? control option command command option
- Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.) Between 1.50 and 2.25 Click to view page 1 of the table. Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. O A. The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) .00 Standard Normal (z) Distribution: Cumulative Area from the LEFT .5000 5398 5793 .6179 .6554 .6915 7257 .7580 7881 .8159 .8413 8643 .8849 .9032 9192 9332 9452 .9554 .9641 9713 9772 .9821 9861 0007 .01 5040 5438 5832 6217 .6591 z=1.50 z=2.25 6950 7291 .7611 7910 .8186 .8438 8665 8869 9049 9207 9345 9463 .9564 9649 .9719 9778 9826 9864 .02 5080 5478 5871 6255 6628 .6985 7324 7642 7939 .8212 8461 8686 8888 .9066 9222 9357 9474 .9573 9656…In a certain population, the mean score on a test is 420. The standard deviation is 105. If the distribution or scores is normal, which of these scores should occur most often. a. 385 b314 c. 540 d. 526Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)
