Draw a sketch. Choose the correct graph below. O A. A 2-1.50 -2.25 The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) POSTLIVE 750O KOS O B. Z-1.50 Z-2.25 Q - X O C. Standard Normal Table (Page 1) NEGATIVE Z Scores Z-1.50 -2.25 0
Draw a sketch. Choose the correct graph below. O A. A 2-1.50 -2.25 The probability of getting a reading between 1.50°C and 2.25°C is (Round to four decimal places as needed.) d Normal Table (Page 2) POSTLIVE 750O KOS O B. Z-1.50 Z-2.25 Q - X O C. Standard Normal Table (Page 1) NEGATIVE Z Scores Z-1.50 -2.25 0
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:Assume that thermometer readings are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius
degrees.)
Between 1.50 and 2.25
Click to view page 1 of the table. Click to view page 2 of the table.
Draw a sketch. Choose the correct graph below.
O A.
The probability of getting a reading between 1.50°C and 2.25°C is
(Round to four decimal places as needed.)
d Normal Table (Page 2)
.00
Standard Normal (z) Distribution: Cumulative Area from the LEFT
.5000
5398
5793
.6179
.6554
.6915
7257
.7580
7881
.8159
.8413
8643
.8849
.9032
9192
9332
9452
.9554
.9641
9713
9772
.9821
9861
0007
.01
5040
5438
5832
6217
.6591
z=1.50 z=2.25
6950
7291
.7611
7910
.8186
.8438
8665
8869
9049
9207
9345
9463
.9564
9649
.9719
9778
9826
9864
.02
5080
5478
5871
6255
6628
.6985
7324
7642
7939
.8212
8461
8686
8888
.9066
9222
9357
9474
.9573
9656
9726
9783
.9830
9868
0000
POSITIVE Z Scores
.03
5120
5517
5910
6293
6664
7019
7357
7673
7967
.8238
8485
8708
8907
.9082
9236
9370
9484
.9582
9664
9732
9788
9834
9871
0901
.04
.5160
5557
.5948
.6331
.6700
.7054
7389
.05
.9875
gand
5199
.5596
5987
6368
.6736
.7088
7422
7734
.7704
7995
.8264
8508
.8729
.8925
.9099
.9251
9382
9495 * 9505
.9591
.9599
.9671
.9678
9738
9744
9793
.9838
8023
.8289
.8531
8749
8944
.9115
9265
9394
.9798
.9842
.9878
aane
.06
5239
5636
.6026
.6406
.6772
7123
7454
.7764
.8051
.8315
.8554
.8770
8962
.9131
.9279
.9406
9515
.9608
.9686
.9750
.9803
.9846
.9881
.07
5279
5675
6064
.6443
.6808
7157
7486
.7794
8078
8340
.8577
8790
.8980
.9147
9292
9418
9525
.9616
9693
9756
.9808
.9850
.9884
2011
.08
5319
5714
.6103
6480
6844
.7190
7517
7823
.8106
.8365
.8599
.8810
.8997
.9162
9306
.9429
9535
.9625
.9699
9761
9812
.9854
.9887
0017
.09
5359
5753
6141
.6517
.6879
.7224
7549
7852
.8133
.8389
.8621
.8830
9015
.9177
.9319
.9441
9545
.9633
9706
.9767
.9817
.9857
.9890
0916
O B.
Z=1.50 z=2.25
Q
Q
✔
- X
C
Standard Normal Table (Page 1)
NEGATIVE z Scores
-3.50
and
lower
-3.4
-3.3
-3.2
-3.1
-3.0
-2.9
-2.8
-2.7
-2.6
-2.5
-2.4
-2.3
-2.2
-2.1
-1.9
-1.8
-1.7
-1.5
-1.4
-1.3
-1.2
.00
0001
,0003
.0005
,0007
.0010
.0013
.0019
Standard Normal (z) Distribution: Cumulative Area from the LEFT
.0026
.0035
0047
0062
.0082
.0107
0139
.0179
.0228
0287
0359
0446
0548
.0668
.0808
0968
1151
1357
.01
0003
.0005
0007
.0009
0013
0018
.0025
0034
0045
0060
0080
0104
0136
0174
0222
0281
0351
0436
0537
0655
0793
0951
1131
1335
.02
0003
.0005
.0006
0009
.0013
0018
.0024
.0033
0044
0059
0078
.0102
0132
0170
0217
0274
0344
0427
0526
.0643
0778
0934
1112
1314
.03
0003
.0004
.0006
0009
0012
.0017
.0023
.0032
0043
0057
.0075
.0099
0129
0166
0212
.0268
.0336
0418
O C.
.0516
0630
0764
.0918
1093
1292
.04
0003
0004
0006
.0008
0012
.0016
0023
.0031
0041
0055
0073
0096
0125
0162
.05
.1075
1271
,0003
.0004
,0006
.0008
.0011
.0016
.0022
0030
,0040
.0054
.0071
.0094
.0122
.0158
0207 .0202
.0256
0262
0329
0409
0505
0618
0749
.0901
0322
0401
z=1.50 z=2.25
* .0495
.0606
.0735
.0885
1056
1251
.06
0003
.0004
0006
0008
0011
.0015
.0021
0029
0039
0052
.0069
.0091
0119
0154
0197
0250
0314
0392
0485
0594
0721
0869
1038
1230
0003
.0004
.0005
Q
.0008
,0011
0015
.0021
.0028
0038
.0051
.0068
.0089
0116
.0150
0192
.0244
.0307
0384
.0475
0582
.0708
0853
1020
1210
Q
.08
.0003
.0004
.0005
0007
0010
.0014
.0020
0027
0037
0049
.0066
0087
0113
0146
.0188
0239
.0301
.0375
0465
.0571
0694
0838
1003
1190
.09
0002
.0003
0005
.0007
0010
.0014
.0019
.0026
0036
.0048
.0064
.0084
0110
0143
.0183
0233
0294
0367
0455
.0559
.0681
0823
0985
1170
X
Expert Solution
Step 1
It is given that thermometer readings are normally distributed with mean 0 and standard deviation 1.
Step by step
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