**Understanding Normal Distributions***Problem Statement:*One graph in the figure represents a normal distribution with mean \( \mu = 7 \) and standard deviation \( \sigma = 1 \). The other graph represents a normal distribution with mean \( \mu = 12 \) and standard deviation \( \sigma = 1 \). Determine which graph is which and explain how you know.*Graph Description:*The diagram includes two normal distribution curves:- **Graph A** (in red)- **Graph B** (in blue)The graphs are labeled with numbers 7 and 12 along the horizontal axis, indicating the means of the distributions.*Options for the Correct Answer:*A. Graph A has a mean of \( \mu = 12 \) and graph B has a mean of \( \mu = 7 \) because a larger mean shifts the graph to the left.B. Graph A has a mean of \( \mu = 12 \) and graph B has a mean of \( \mu = 7 \) because a larger mean shifts the graph to the right.C. Graph A has a mean of \( \mu = 7 \) and graph B has a mean of \( \mu = 12 \) because a larger mean shifts the graph to the left.D. Graph A has a mean of \( \mu = 7 \) and graph B has a mean of \( \mu = 12 \) because a larger mean shifts the graph to the right.*Explanation:*In the context of normal distributions, increasing the mean \( \mu \) shifts the graph to the right. Therefore, Graph A corresponds to a mean of \( \mu = 7 \) and Graph B corresponds to a mean of \( \mu = 12 \). The correct choice is D.

From the given graph as follows: It can be seen that Graph A has mean 7 and Graph B has mean 12.

One graph in the figure represents a normal distribution with mean u=7 and standard deviation o= 1. The other graph represents a normal distribution with mean p= 12 and standard deviation o = 1. Determine which graph is which and explain how you know. * 12 Choose the correct answer below. O A. Graph A has a mean of u = 12 and graph B has a mean of u=7 because a larger mean shifts the graph to the left. O B. Graph A has a mean of u = 12 and graph B has a mean of u=7 because a larger mean shifts the graph to the right. OC. Graph A has a mean of u = 7 and graph B has a mean of u = 12 because a larger mean shifts the graph to the left. O D. Graph A has a mean of u = 7 and graph B has a mean of u = 12 because a larger mean shifts the graph to the right.

One graph in the figure represents a normal distribution with mean u=7 and standard deviation o= 1. The other graph represents a normal distribution with mean p= 12 and standard deviation o = 1. Determine which graph is which and explain how you know. * 12 Choose the correct answer below. O A. Graph A has a mean of u = 12 and graph B has a mean of u=7 because a larger mean shifts the graph to the left. O B. Graph A has a mean of u = 12 and graph B has a mean of u=7 because a larger mean shifts the graph to the right. OC. Graph A has a mean of u = 7 and graph B has a mean of u = 12 because a larger mean shifts the graph to the left. O D. Graph A has a mean of u = 7 and graph B has a mean of u = 12 because a larger mean shifts the graph to the right.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Determine whether the statement is true or false. As the size of a sample increases, the mean of the distribution of sample means increase. choose 1. a.False , as the size of a sample increases, the mean of the distribution of sample means decrease b. False as the sample increases the mean of distribution of sample means does not change. c. True.
Which point would most likely be considered an outlier if it was added to the data in the table? (2,19),(5,11),(7,14) or (10,22)
Create a histogram for each of your variables using the same classes that you used for your frequency table. Discuss the distribution of each histogram. Based on the shape of each histogram, would the mean or median be a better measure of center for each variable? Explain.The graphs go up by 2.5. male stats: mean-18.1667 standard deviation-2.7796 N-183 female stats: mean-20.8973 standard deviation-3.3859 N-183
Which of the three brands had the smallest mean lifetime? Try doing this without a calculator- just compare the three plots.
College students recorded the self-reported weights (in pounds) of some community college male baseball players and male soccer players. Write a brief comparison of the distributions of weights for the two groups. Include appropriate graphics. Click the icon to view the weights of male baseball and soccer players. Make dotplots using the same axis with one set of data above the other. Choose the correct graph below. Click here to view dotplots C Click here to view dotplots D. Click here to view dofplots B. O Click here to view dotplats A Compare the shape, center, and variation (and mention outliers if there were any). Baseball players' weights are to weigh with The soccer players' weights are with The baseball players tend soccer players. The baseball players have a distribution with variability than the soccer players' distribution. Data table Baseball Players' Weights: 190,192,183,183,190,187,187,187,192,192,184,184,184,192,187,228,183,190,180,184,183,187,184,184,205,187,230 Soccer…
Which of the following is shown on the scatter plot below? 10 8 6. 4 2 X. 2 4 6 8 10 Choose cluster negative association outlier
Q12
What is the FSTAT and P-Value?
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.7 degrees. Low Temperature (°F) Frequency 40-44 45-49 50-54 10 55-59 6 60-64 Find the mean of the frequency distribution, Round to the nearest tenth as needed. Which of the following best describes the relationship between the computed mean and the actual mean?
We've plotted our data on a numb er line in a way intended to show clearly that the 4 appears twi ce in our data set. Exercise 1. Find the means for each dat a set given. Plot the data set and its mean. 1. -5,5 2. -3,-2,5 3. 11, 13, 15 4. 11, 13, 14 5. 2,3,-2,-3 6. 2,3,-1,-4 7. 1,7 8. 1,7,7 9. 1,7,7,7 10. 2,2,5, 2,5, 5, 2,2, 2 11. a dataset with four 3s, six 5s, and one 2. 12. a dataset with five 10s, two 7s and fourteen 2s
For each sets of data create a stem and leaf plot and then make the histogram using the appropriate number of class intervals. 1. We are given the data 14.1 ; 13.3 ; 14.4 ; 13.4 ; 12.7; 11.3 ; 13.3 12.2 ; 14.8 ; 14,7 ; 13.1 ; 11.3 ; 12.9 ; 12.0 11.9 ; 11.7 ; 12.8 ; 12.6 ; 13.1; 12.6 ; 12.9 13.8 ; 11.4 ; 11.1; 14.2 ; 13.8 ; 14.1 ; 13.6 (a) Construct the stem-and-leaf display for these data. Calculate the median. (b) Construct a frequency distribution and a histogram.
Which is the line of best fit for the data shown in the table? y 2 4 6. 6. 8. 8. 9. 9. O y = 0.72x+3.04 O y = 2.68x + 0.75 O y = 0.75x+ 2.68 O y = 2.68x + 0.70 96 XHN456