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The number of light bulbs that can be expected to last less than 1540 hr is.

The number of light bulbs that can be expected to last less than 1540 hr is.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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□ Area x-μ 0 AREA UNDER A NORMAL CURVE TO THE LEFT OF Z, WHERE Z = .00 .01 .05 .07 .08 .02 .03 .0003 .0003 .0005 .0005 .0004 .0006 -3.2 .0006 -3.1 .0010 .0009 .0009 .0009 .0008 -3.0 .0013 .0013 .0013 .0012 .0012 -3.4 .0003 .0003 .0005 -3.3 .0007 .0007 .0006 .04 .0003 .0003 .0003 .0003 .0003 .0004 .0004 .0004 .0004 .0004 0006 .0005 .0005 .0006 .0008 0008 0008 .0007 0011 0011 0011 .0010 .06 .09 .0002 .0003 .0005 0007 .0010 -2.9 .0019 .0018 .0017 .0017 .0016 .0016 0015 .0015 .0014 0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 0021 .0020 .0019 -2.7 0035 0034 0033 .0032 .0031 .0030 .0029 .0028 .0027 .0026 -2.6 .0047 .0045 .0044 .0043 .0041 .0040 .0039 0038 0037 .0036 -2.5 .0062 .0060 .0059 .0057 .0055 .0054 .0052 0051 .0049 .0048 .0082 .0080 .0078 0075 .0073 .0071 .0069 0068 .0066 .0064 -2.4 AREA UNDER A NORMAL CURVE (continued) .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 -.4 .3446 3409 3372 3336 3300 3264 3228 3192 .3156 .3121 -.3 .3821 3783 3745 3707 3669 3632 3594 3557 3520 3483 -.2 4207 4168 4129 4090 4052 4013 3974 .3936 3897 3859 4602 4562 4522 4483 4443 4404 4364 4325 4286 4247 .5000 4960 4920 4880 4840 4801 4761 4721 4681 4641 5000 5040 5080 5120 5160 5199 5239 5279 5319 5359 5398 5438 5478 .5517 5557 5596 5636 .5675 .5714 5753 5793 5832 5871 5910 5948 5987 .6026 .6064 .6103 .6141 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 .6950 .6985 .7019 .7054 7088 .7123 .6915 .7190 .7157 .7257 .7291 .7324 7357 .7389 7422 7454 .7486 .7517 .7 .7580 .7611 .7642 .7673 .7704 7734 .7764 .7794 .7823 .7881 .7910 .7939 7967 .7995 .8023 .8051 .8078 .8106 .9 .8159 .8186 .8212 8238 .8264 .8365 1.0 .8413 .8438 .8461 .8485 8508 1.1 .8643 .8665 .8686 8708 8729 1.2 .8849 .8869 8888 .8907 .8925 1.3 .9032 9049 9066 9082 .9099 1.4 .9192 9207 .9222 9236 9251 .8 .8289 .8315 .8340 .8531 .8554 .8577 8599 8749 .8770 .8790 .8810 .8944 8962 .8980 .8997 9115 9131 9147 9162 .9265 .9278 9292 9306 -.0 .0 .1 .2 درا - .3 .4 567 .5 .6 7224 7549 .7852 8133 .8389 .8621 .8830 .9015 9177 9319
Transcribed Image Text:□ Area x-μ 0 AREA UNDER A NORMAL CURVE TO THE LEFT OF Z, WHERE Z = .00 .01 .05 .07 .08 .02 .03 .0003 .0003 .0005 .0005 .0004 .0006 -3.2 .0006 -3.1 .0010 .0009 .0009 .0009 .0008 -3.0 .0013 .0013 .0013 .0012 .0012 -3.4 .0003 .0003 .0005 -3.3 .0007 .0007 .0006 .04 .0003 .0003 .0003 .0003 .0003 .0004 .0004 .0004 .0004 .0004 0006 .0005 .0005 .0006 .0008 0008 0008 .0007 0011 0011 0011 .0010 .06 .09 .0002 .0003 .0005 0007 .0010 -2.9 .0019 .0018 .0017 .0017 .0016 .0016 0015 .0015 .0014 0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 0021 .0020 .0019 -2.7 0035 0034 0033 .0032 .0031 .0030 .0029 .0028 .0027 .0026 -2.6 .0047 .0045 .0044 .0043 .0041 .0040 .0039 0038 0037 .0036 -2.5 .0062 .0060 .0059 .0057 .0055 .0054 .0052 0051 .0049 .0048 .0082 .0080 .0078 0075 .0073 .0071 .0069 0068 .0066 .0064 -2.4 AREA UNDER A NORMAL CURVE (continued) .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 -.4 .3446 3409 3372 3336 3300 3264 3228 3192 .3156 .3121 -.3 .3821 3783 3745 3707 3669 3632 3594 3557 3520 3483 -.2 4207 4168 4129 4090 4052 4013 3974 .3936 3897 3859 4602 4562 4522 4483 4443 4404 4364 4325 4286 4247 .5000 4960 4920 4880 4840 4801 4761 4721 4681 4641 5000 5040 5080 5120 5160 5199 5239 5279 5319 5359 5398 5438 5478 .5517 5557 5596 5636 .5675 .5714 5753 5793 5832 5871 5910 5948 5987 .6026 .6064 .6103 .6141 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 .6950 .6985 .7019 .7054 7088 .7123 .6915 .7190 .7157 .7257 .7291 .7324 7357 .7389 7422 7454 .7486 .7517 .7 .7580 .7611 .7642 .7673 .7704 7734 .7764 .7794 .7823 .7881 .7910 .7939 7967 .7995 .8023 .8051 .8078 .8106 .9 .8159 .8186 .8212 8238 .8264 .8365 1.0 .8413 .8438 .8461 .8485 8508 1.1 .8643 .8665 .8686 8708 8729 1.2 .8849 .8869 8888 .8907 .8925 1.3 .9032 9049 9066 9082 .9099 1.4 .9192 9207 .9222 9236 9251 .8 .8289 .8315 .8340 .8531 .8554 .8577 8599 8749 .8770 .8790 .8810 .8944 8962 .8980 .8997 9115 9131 9147 9162 .9265 .9278 9292 9306 -.0 .0 .1 .2 درا - .3 .4 567 .5 .6 7224 7549 .7852 8133 .8389 .8621 .8830 .9015 9177 9319
Suppose that the life expectancy of a certain brand of nondefective light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr. If 50,000 of these bulbs are produced, how many can be expected to last less than 1540 hr? Use the following links to view the Standard Normal Distribution table. Click here to view page 1 of the table. Click here to view page 2 of the table. The number of light bulbs that can be expected to last less than 1540 hr is ■.
Transcribed Image Text:Suppose that the life expectancy of a certain brand of nondefective light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr. If 50,000 of these bulbs are produced, how many can be expected to last less than 1540 hr? Use the following links to view the Standard Normal Distribution table. Click here to view page 1 of the table. Click here to view page 2 of the table. The number of light bulbs that can be expected to last less than 1540 hr is ■.
Expert Solution
Step 1

here given ,

Suppose that the life expectancy of a certain brand of non defective light bulbs is normally distributed, with a mean life of 1300 hr and a standard deviation of 150 hr.

n =  50000

mean  =  1300

standard deviation  =  150 
x = life of light bulb in hour 

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