ssume that X has a normal distribution. ind the probability that X is greater than

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### Understanding Normal Distribution

Understanding how to use the normal distribution is an essential skill in statistics. Given the characteristics of a dataset, you can determine the likelihood of a particular outcome. Let's explore this concept further using an example.

### Example Question

Assume that \( X \) has a normal distribution. The mean is \( \mu = 15.2 \) and the standard deviation is \( \sigma = 0.9 \).

#### Problem:
Find the probability that \( X \) is greater than 15.2.

To find this probability, you can use the Z-table. The Z-table helps you understand the proportion of values to the left of a given Z-score in a standard normal distribution.

Here's the question and the options:

1. Click to view page 1 of the table. Click to view page 2 of the table.

#### Select the correct option:
- A. 1.0000
- B. 0.9998
- C. 0.0003
- D. 0.5000

### Steps to Solve:
1. **Identify the given data:**
   - Mean (\(\mu\)) = 15.2
   - Standard Deviation (\(\sigma\)) = 0.9
   
2. **Calculate the Z-score:**
   The Z-score formula is: 
   \[
   Z = \frac{(X - \mu)}{\sigma}
   \]
   Here, since we are finding \( P(X > 15.2) \):
   \[
   Z = \frac{(15.2 - 15.2)}{0.9} = 0
   \]

3. **Find the probability:**
   Use the Z-table to find the probability corresponding to the Z-score.
   For \( Z = 0 \), the Z-table shows that 50% of the values lie to the left of \( Z = 0 \).
   Therefore, \( P(X > 15.2) \) is the remaining 50%, since it’s a symmetric distribution.
   
   So, the probability:
   \[
   P(X > 15.2) = 0.5000
   \]

### Final Answer:
- D. 0.5000

Understanding how to work with the normal distribution and use the Z-table is crucial for solving such problems. It is a fundamental concept used across various fields such
Transcribed Image Text:### Understanding Normal Distribution Understanding how to use the normal distribution is an essential skill in statistics. Given the characteristics of a dataset, you can determine the likelihood of a particular outcome. Let's explore this concept further using an example. ### Example Question Assume that \( X \) has a normal distribution. The mean is \( \mu = 15.2 \) and the standard deviation is \( \sigma = 0.9 \). #### Problem: Find the probability that \( X \) is greater than 15.2. To find this probability, you can use the Z-table. The Z-table helps you understand the proportion of values to the left of a given Z-score in a standard normal distribution. Here's the question and the options: 1. Click to view page 1 of the table. Click to view page 2 of the table. #### Select the correct option: - A. 1.0000 - B. 0.9998 - C. 0.0003 - D. 0.5000 ### Steps to Solve: 1. **Identify the given data:** - Mean (\(\mu\)) = 15.2 - Standard Deviation (\(\sigma\)) = 0.9 2. **Calculate the Z-score:** The Z-score formula is: \[ Z = \frac{(X - \mu)}{\sigma} \] Here, since we are finding \( P(X > 15.2) \): \[ Z = \frac{(15.2 - 15.2)}{0.9} = 0 \] 3. **Find the probability:** Use the Z-table to find the probability corresponding to the Z-score. For \( Z = 0 \), the Z-table shows that 50% of the values lie to the left of \( Z = 0 \). Therefore, \( P(X > 15.2) \) is the remaining 50%, since it’s a symmetric distribution. So, the probability: \[ P(X > 15.2) = 0.5000 \] ### Final Answer: - D. 0.5000 Understanding how to work with the normal distribution and use the Z-table is crucial for solving such problems. It is a fundamental concept used across various fields such
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