Solve the following problem and show your complete solutions. Explain your answer for better understanding. The length of time, L hours, that a phone will work before it needs charging is normally distributed with a mean of 100 hours and a standard deviation of 15 hours. Find the probability that a randomly selected phone will work greater than 127 hours before it needs charging.
Solve the following problem and show your complete solutions. Explain your answer for better understanding. The length of time, L hours, that a phone will work before it needs charging is normally distributed with a mean of 100 hours and a standard deviation of 15 hours. Find the probability that a randomly selected phone will work greater than 127 hours before it needs charging.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Solve the following problem and show your complete solutions. Explain your answer for better understanding.

Transcribed Image Text:Solve the following problem and show your complete solutions. Explain your answer for better
understanding.
The length of time, L hours, that a phone will work before it needs charging is
normally distributed with a mean of 100 hours and a standard deviation of 15 hours.
Find the probability that a randomly selected phone will work greater than 127 hours
before it needs charging.
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