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A parallel-plate capacitor is made of two square plates 30 cm on a side and 1 mm opnectod to a 00-V battery

A parallel-plate capacitor is made of two square plates 30 cm on a side and 1 mm opnectod to a 00-V battery

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Parallel-Plate Capacitor Problem** A parallel-plate capacitor is made of two square plates, each 30 cm on a side, and 1 mm apart. The capacitor is connected to a 90 V battery. --- **Questions:** a. **What is the energy stored in the capacitor?** - Energy stored in the capacitor is \(3 \, \mu \text{J}\). b. **With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now?** - Energy now stored in the capacitor is \(2E-\). c. **This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now?** - Energy now stored in the capacitor is [Blank] \(\mu \text{J}\). d. **Comparing your results in (b) and (c) above, it makes sense that the energy stored in the capacitor increases in (c), because the work done in separating the plates is stored as the electrostatic potential energy.** - **In (b), why does the energy decrease even though work is done in separating the plates?** - The possible explanations include: - The energy stored in the capacitor does not include work done on the charges. - The energy is not conserved in static electricity. - The energy due to work done goes into the battery. - A negative work is done in separating the plates. --- **Explanation:** The problem involves understanding the changes in energy stored in a capacitor when the separation between the plates changes, with or without the battery connected. This illustrates concepts like conservation of energy and how energy distribution varies with electrical setup changes.
Transcribed Image Text:**Parallel-Plate Capacitor Problem** A parallel-plate capacitor is made of two square plates, each 30 cm on a side, and 1 mm apart. The capacitor is connected to a 90 V battery. --- **Questions:** a. **What is the energy stored in the capacitor?** - Energy stored in the capacitor is \(3 \, \mu \text{J}\). b. **With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now?** - Energy now stored in the capacitor is \(2E-\). c. **This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now?** - Energy now stored in the capacitor is [Blank] \(\mu \text{J}\). d. **Comparing your results in (b) and (c) above, it makes sense that the energy stored in the capacitor increases in (c), because the work done in separating the plates is stored as the electrostatic potential energy.** - **In (b), why does the energy decrease even though work is done in separating the plates?** - The possible explanations include: - The energy stored in the capacitor does not include work done on the charges. - The energy is not conserved in static electricity. - The energy due to work done goes into the battery. - A negative work is done in separating the plates. --- **Explanation:** The problem involves understanding the changes in energy stored in a capacitor when the separation between the plates changes, with or without the battery connected. This illustrates concepts like conservation of energy and how energy distribution varies with electrical setup changes.
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