(a) What is the energy (in J) stored in the 40.0 µF capacitor of a heart defibrillator charged to 8.90 x 103 v? (b) Find the amount of stored charge (in mC). mc
(a) What is the energy (in J) stored in the 40.0 µF capacitor of a heart defibrillator charged to 8.90 x 103 v? (b) Find the amount of stored charge (in mC). mc
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![### Problem Statement for Educational Purposes
#### Question (a)
What is the energy (in Joules) stored in the 40.0 μF capacitor of a heart defibrillator charged to \( 8.90 \times 10^3 \) V?
> [Your answer here] J
#### Question (b)
Find the amount of stored charge (in milliCoulombs).
> [Your answer here] mC
---
This exercise involves calculating the energy stored in a capacitor and finding the charge stored within it based on given parameters. To solve these problems, the following formulas are utilized:
- **Energy (E) in a capacitor**:
\[
E = \frac{1}{2} C V^2
\]
where \( C \) is the capacitance and \( V \) is the voltage.
- **Charge (Q) stored in a capacitor**:
\[
Q = C \times V
\]
where \( C \) is the capacitance and \( V \) is the voltage.
Use these formulas to calculate and fill in the blanks for the energy and stored charge.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dee1ec3-7459-4c74-952e-4564ff4298fd%2Ffc987736-dc94-49eb-9136-1854e647e871%2Fmuvwmpr_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement for Educational Purposes
#### Question (a)
What is the energy (in Joules) stored in the 40.0 μF capacitor of a heart defibrillator charged to \( 8.90 \times 10^3 \) V?
> [Your answer here] J
#### Question (b)
Find the amount of stored charge (in milliCoulombs).
> [Your answer here] mC
---
This exercise involves calculating the energy stored in a capacitor and finding the charge stored within it based on given parameters. To solve these problems, the following formulas are utilized:
- **Energy (E) in a capacitor**:
\[
E = \frac{1}{2} C V^2
\]
where \( C \) is the capacitance and \( V \) is the voltage.
- **Charge (Q) stored in a capacitor**:
\[
Q = C \times V
\]
where \( C \) is the capacitance and \( V \) is the voltage.
Use these formulas to calculate and fill in the blanks for the energy and stored charge.
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