Find the total capacitance Cot of the combination of capacitors shown in the figure, where C¡ = 5.15 µF, C2 = 3.55 µF, C3 = 6.25 µF, C4 = 1.75 µF, 0.750 µF, and C, = 15.0 µF. %3D C5 %3D %3D Clot = 23.876436781 uF Incorrect Question Credit: OpenStax College Physics

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Find the total capacitance Cot Oof the combination of
capacitors shown in the figure, where C
5.15 µF,
C = 3.55 µF, C; = 6.25 µF, C4 = 1.75 µF,
%3D
C5 = 0.750 µF, and C6 = 15.0 µF.
%3D
%3D
Ctot =
23.876436781
µF
Incorrect
Question Credit: OpenStax College Physics
Transcribed Image Text:Find the total capacitance Cot Oof the combination of capacitors shown in the figure, where C 5.15 µF, C = 3.55 µF, C; = 6.25 µF, C4 = 1.75 µF, %3D C5 = 0.750 µF, and C6 = 15.0 µF. %3D %3D Ctot = 23.876436781 µF Incorrect Question Credit: OpenStax College Physics
Expert Solution
Step 1

given that C=5.15μF,

C=3.55μF,

C3=6.25μF,

C4=1.75μF,

C5=0.75μF,

C6=15μF

C5 and C6 are in parallel thus net of C5 and C6, C56= C5+C6=15.75μF

and C4 is connected in series with it so net capacitance of 4,5,6 = C4C56C4+C56=1.575μF

 

 

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