A non-isothermal batch reactor can be described by the following equations: dC e(-10/(T+273)) .C dt == = dT = 1000 e(-10/(T+273)) .C-10(T-20) dt Where C is the concentration of the reactant and T is the temperature of the reactor. Initially the reactor is at 15°C and has a concentration of reactant C of 1.0 gmol/L. Find the concentration and temperature of the reactor as a function of time. Apply Runge-kutta 4th order Method for two steps with time step size of 0.0625 sec.
A non-isothermal batch reactor can be described by the following equations: dC e(-10/(T+273)) .C dt == = dT = 1000 e(-10/(T+273)) .C-10(T-20) dt Where C is the concentration of the reactant and T is the temperature of the reactor. Initially the reactor is at 15°C and has a concentration of reactant C of 1.0 gmol/L. Find the concentration and temperature of the reactor as a function of time. Apply Runge-kutta 4th order Method for two steps with time step size of 0.0625 sec.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![A non-isothermal batch reactor can be described by the following equations:
dC
-=-e(-10/(T+273)) .C
dt
dT
dt
= 1000 e(-10/(T+273)) .C-10(T-20)
Where is the concentration of the reactant and I is the temperature of the reactor.
Initially the reactor is at 15°C and has a concentration of reactant C of 1.0 gmol/L. Find
the concentration and temperature of the reactor as a function of time. Apply Runge-kutta
4th order Method for two steps with time step size of 0.0625 sec.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa20daa94-baaa-4ca4-9d35-7c66cbaaae97%2F697c2784-6b73-451b-87a5-80b330e99acb%2Fpcgc316_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A non-isothermal batch reactor can be described by the following equations:
dC
-=-e(-10/(T+273)) .C
dt
dT
dt
= 1000 e(-10/(T+273)) .C-10(T-20)
Where is the concentration of the reactant and I is the temperature of the reactor.
Initially the reactor is at 15°C and has a concentration of reactant C of 1.0 gmol/L. Find
the concentration and temperature of the reactor as a function of time. Apply Runge-kutta
4th order Method for two steps with time step size of 0.0625 sec.
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