4. For the combustion of methane, the unbalanced reaction is: CH4 + O₂ => CO₂ + H₂O The reaction occurs in a steady state reactor, which is operated at conditions where all of the reactants and products are gaseous. A stream of air supplies the oxygen to the reactor, and it is provided in excess by 25%. All left over reactants and created products leave the reactor in a single stream. What would the fractional conversion of methane be that resulted in a mole fraction of methane in the outlet of 0.05?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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4. For the combustion of methane, the unbalanced reaction is:
CH4 + O₂ => CO₂ + H₂O
The reaction occurs in a steady state reactor, which is operated at conditions where all of the
reactants and products are gaseous. A stream of air supplies the oxygen to the reactor, and it is
provided in excess by 25%. All left over reactants and created products leave the reactor in a
single stream. What would the fractional conversion of methane be that resulted in a mole
fraction of methane in the outlet of 0.05?
Transcribed Image Text:4. For the combustion of methane, the unbalanced reaction is: CH4 + O₂ => CO₂ + H₂O The reaction occurs in a steady state reactor, which is operated at conditions where all of the reactants and products are gaseous. A stream of air supplies the oxygen to the reactor, and it is provided in excess by 25%. All left over reactants and created products leave the reactor in a single stream. What would the fractional conversion of methane be that resulted in a mole fraction of methane in the outlet of 0.05?
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