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4. Light olefin is produced by cracking propane. Two cracking reactions occur in a steady- flow reactor at 1.2 bar and 750 K under ideal gas conditions: C3H8(g) → C3H6(g) + H₂(g) (1) C3H8(g) → C₂H4(g) + CH4(g) (II) For an initial amount of 1 mol propane, calculate the product composition if both reactions KII = 21.328. go to equilibrium. At 750 K, the equilibrium constants are: K₁ = 0.016

4. Light olefin is produced by cracking propane. Two cracking reactions occur in a steady- flow reactor at 1.2 bar and 750 K under ideal gas conditions: C3H8(g) → C3H6(g) + H₂(g) (1) C3H8(g) → C₂H4(g) + CH4(g) (II) For an initial amount of 1 mol propane, calculate the product composition if both reactions KII = 21.328. go to equilibrium. At 750 K, the equilibrium constants are: K₁ = 0.016

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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4. Light olefin is produced by cracking propane. Two cracking reactions occur in a steady- flow reactor at 1.2 bar and 750 K under ideal gas conditions: C3H8(g) → C3H6(g) + H₂(g) (I) C3H8(g) → C₂H4(g) + CH4(g) (II) For an initial amount of 1 mol propane, calculate the product composition if both reactions go to equilibrium. At 750 K, the equilibrium constants are: K₁ = 0.016 KII = 21.328.
Transcribed Image Text:4. Light olefin is produced by cracking propane. Two cracking reactions occur in a steady- flow reactor at 1.2 bar and 750 K under ideal gas conditions: C3H8(g) → C3H6(g) + H₂(g) (I) C3H8(g) → C₂H4(g) + CH4(g) (II) For an initial amount of 1 mol propane, calculate the product composition if both reactions go to equilibrium. At 750 K, the equilibrium constants are: K₁ = 0.016 KII = 21.328.
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