A model of a submarine with a mass of 10 kg moves in the sea. If the resistance of the seawater to motion is a function of velocity, (R(v) = -vvv) and the initial velocity of the model are 10 m /s. How many seconds does it take for the model to reach a speed of 5 meters per second? dv -> dt → dt = dv → m EF = ma → R = m t-0 = S"dv Vo R %3D
A model of a submarine with a mass of 10 kg moves in the sea. If the resistance of the seawater to motion is a function of velocity, (R(v) = -vvv) and the initial velocity of the model are 10 m /s. How many seconds does it take for the model to reach a speed of 5 meters per second? dv -> dt → dt = dv → m EF = ma → R = m t-0 = S"dv Vo R %3D
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S1) Please solve this question numerically method
Transcribed Image Text:A model of a submarine with a mass of 10 kg moves in the sea. If the resistance of the seawater to
motion is a function of velocity, (R(v) = -vvv) and the initial velocity of the model are 10 m /s. How
many seconds does it take for the model to reach a speed of 5 meters per second?
dv
m
vm
EF = ma R = m
dt
- dt =
R
dv t-0 =
Vo R
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