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14. * A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is five times greater that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child? 15. * Suppose Figure P11.3 descrihes the dionl than

14. * A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is five times greater that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child? 15. * Suppose Figure P11.3 descrihes the dionl than

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problem 14. The last person did the wrong problem. Please show formula from equation sheet.
ng leoinov c mol gasd zeem A llug nedi no v (m/s) +5 pinsdbom Inion inge 0. 0.2 0.3 0.1 edh mulubreq olgmie obinoM Figure P11.11lodt blooda ndV -5 bu ono) noillic qu bouga Aonlo zida HiW (d) Sh 11.2 EXAMPLES OF SIMPLE ogo odi o o HARMONIC MOTION 12. The period of oscillation for a mass-on-a-spring system is 0.22 s. If m 3.5 kg, what is the spring constant of the spring? 13. Consider the mass on a spring in Figure 11.6. If the spring constant is k = 30 N/m and the mass is m = period? 14. * A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is five times greater than that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child? 15. O Suppose Figure P11.3 describes the displacement of a mass- on-a-spring harmonic oscillator. (a) If the mass is m what is the spring constant? (b) Estimate the velocity and at 5.0 s. (c) Estimate the acceleration at 1.5 s. (d) Estimate the maximum acceleration. %3D 2.5 kg, what is the 2.0 kg, at t = 4.0 s ah nh onom vd 29gasdo Seulubom gouOY 10gs
Transcribed Image Text:ng leoinov c mol gasd zeem A llug nedi no v (m/s) +5 pinsdbom Inion inge 0. 0.2 0.3 0.1 edh mulubreq olgmie obinoM Figure P11.11lodt blooda ndV -5 bu ono) noillic qu bouga Aonlo zida HiW (d) Sh 11.2 EXAMPLES OF SIMPLE ogo odi o o HARMONIC MOTION 12. The period of oscillation for a mass-on-a-spring system is 0.22 s. If m 3.5 kg, what is the spring constant of the spring? 13. Consider the mass on a spring in Figure 11.6. If the spring constant is k = 30 N/m and the mass is m = period? 14. * A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is five times greater than that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child? 15. O Suppose Figure P11.3 describes the displacement of a mass- on-a-spring harmonic oscillator. (a) If the mass is m what is the spring constant? (b) Estimate the velocity and at 5.0 s. (c) Estimate the acceleration at 1.5 s. (d) Estimate the maximum acceleration. %3D 2.5 kg, what is the 2.0 kg, at t = 4.0 s ah nh onom vd 29gasdo Seulubom gouOY 10gs
" for uolume i no MusH start wlone of These egechuns Physics 104 Equation Sheet k = 9.0 x 10° Nm?/C? h = 6.63 x 10 34 Js = 4.14 x 10 15 eVs lo = 10 W/m² me = 9.11 x 10 31 kg Ho = 4n x 10 N/A? C = 3.00 x 10 m/s e = 1.6 x 1019 C E = 8.85 x 102 C/Nm2 m, = 1.67 x 1027 kg nair = 1.00 nwater = 1.33 nsoap = 1.50 Vsound = 340 m/s Wsilver = 4.74 eV 1 eV = 1.6 x 10 1º J F = kqıq2/r? E = kQ/r? F = qE C = q/AV PE = kq.92/r V = kQ/r APE = qAV C = E0A/d AV = -EAx APEE = -WE = -qEd PE = % QAV AV = IR 1/Rea = E, 1/R, P = IAV Reg = E, R, | = Aq/At F = qvB sino EMF = NA Ds/At R = pL/A F = ILB sinO B = Hol/2nr B = Ho nl EMF = NBAW sin(wt) OB = BA cosO įV1 = 12 V2 Vi/V2 = N1/N2 Frequences. W = 2nf = f = 1/T v = fA F = -kAx n= c/v PE = % kAx? V= An =Aair/n fs fo = ni sino1 = n2 sinO2 B = 10 log10 (1/lo) 12/l1 = r/r;? d sino = (m + ½ )a 1/o + 1/i = 1/f fo = f(1 ± °°/) m = -i/o d sino = mA f = R/2 P = 1/f E = hf Rn = (0.0529 nm) n² A = h/mv = h/p A-X' = (h/mc)(1 – cosO) Am T = 2.90 x 10 mK En = -13.6eV/n? AxAp, 2 h/4 KEmax = hf - W L= nh/2n ΔΕΔ h /4π FEmg sine
Transcribed Image Text:" for uolume i no MusH start wlone of These egechuns Physics 104 Equation Sheet k = 9.0 x 10° Nm?/C? h = 6.63 x 10 34 Js = 4.14 x 10 15 eVs lo = 10 W/m² me = 9.11 x 10 31 kg Ho = 4n x 10 N/A? C = 3.00 x 10 m/s e = 1.6 x 1019 C E = 8.85 x 102 C/Nm2 m, = 1.67 x 1027 kg nair = 1.00 nwater = 1.33 nsoap = 1.50 Vsound = 340 m/s Wsilver = 4.74 eV 1 eV = 1.6 x 10 1º J F = kqıq2/r? E = kQ/r? F = qE C = q/AV PE = kq.92/r V = kQ/r APE = qAV C = E0A/d AV = -EAx APEE = -WE = -qEd PE = % QAV AV = IR 1/Rea = E, 1/R, P = IAV Reg = E, R, | = Aq/At F = qvB sino EMF = NA Ds/At R = pL/A F = ILB sinO B = Hol/2nr B = Ho nl EMF = NBAW sin(wt) OB = BA cosO įV1 = 12 V2 Vi/V2 = N1/N2 Frequences. W = 2nf = f = 1/T v = fA F = -kAx n= c/v PE = % kAx? V= An =Aair/n fs fo = ni sino1 = n2 sinO2 B = 10 log10 (1/lo) 12/l1 = r/r;? d sino = (m + ½ )a 1/o + 1/i = 1/f fo = f(1 ± °°/) m = -i/o d sino = mA f = R/2 P = 1/f E = hf Rn = (0.0529 nm) n² A = h/mv = h/p A-X' = (h/mc)(1 – cosO) Am T = 2.90 x 10 mK En = -13.6eV/n? AxAp, 2 h/4 KEmax = hf - W L= nh/2n ΔΕΔ h /4π FEmg sine
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