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Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through its diameter at a constant rate off= 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to the rotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0. Part (a) Select the correct expression for the time-dependent magnetic flux through the loop. SchematicChoice : D = TB cos(ft)r² $ = 2nB cos(27ft)r² ¢ = TB cos(27 ft)r 1 Ф B cos(2n ft)r² = #B cos(27 f)r² 4 = «B cos(2nft)r² Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part (а).В. SchematicChoice : E = 2n² fr² B sin(27f) Ɛ= 2n² fr²B cos(2nf) E = ar² B sin(27 ft) E = ar² B cos(2n ft) E = 2n² fr² B cos(27 ft) E = 2n² fr²B sin(27 ft) %3D %3D %3D

Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through its diameter at a constant rate off= 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to the rotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0. Part (a) Select the correct expression for the time-dependent magnetic flux through the loop. SchematicChoice : D = TB cos(ft)r² $ = 2nB cos(27ft)r² ¢ = TB cos(27 ft)r 1 Ф B cos(2n ft)r² = #B cos(27 f)r² 4 = «B cos(2nft)r² Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part (а).В. SchematicChoice : E = 2n² fr² B sin(27f) Ɛ= 2n² fr²B cos(2nf) E = ar² B sin(27 ft) E = ar² B cos(2n ft) E = 2n² fr² B cos(27 ft) E = 2n² fr²B sin(27 ft) %3D %3D %3D

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through its diameter at a constant rate of f = 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to the rotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0. Part (a) Select the correct expression for the time-dependent magnetic flux through the loop. SchematicChoice : + = TB cos(ft)r² O = 27B cos(27 ft)r² O = TB cos(27 ft)r 1 B cos(2T ft)r² D = TB cos(27 f )r² = TB cos(27 ft)r² Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part (а).В. SchematicChoice : E = 2n² fr² B sin(27f) E= 2n² fr²B cos(27f) E = ar² B cos(27 ft) E = 2n² fr² B cos(2rft) E = 2n² fr²B sin(2n ft) = ar²B sin(27 ft) Part (d) Calculate the induced emf in the loop, in volts, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (e) Select the expression for the induced current in the loop based on the expression you entered in part (c). SchematicChoice : 4n f2r³B 473 f²r³B - sin(27 ft) I = cos(27 ft) I= R sin(27 f) I = R I = 2n² fr² B sin(27f) I= 2n² fr² B sin(2rft) 27² fr²B I 2E ) sin(27 ft) R Part (f) Find the induced current in the loop, in amperes, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. I =
Transcribed Image Text:Problem 8: A circular wire loop of radius r = 0.15 m and resistance R = 8.5 Q rotates about a shaft through its diameter at a constant rate of f = 5.35 Hz in a uniform B = 0.37-T magnetic field directed perpendicular to the rotation axis. The plane of the loop is perpendicular to the magnetic field at time t = 0. Part (a) Select the correct expression for the time-dependent magnetic flux through the loop. SchematicChoice : + = TB cos(ft)r² O = 27B cos(27 ft)r² O = TB cos(27 ft)r 1 B cos(2T ft)r² D = TB cos(27 f )r² = TB cos(27 ft)r² Part (b) Find the value of the magnetic flux through the loop, in webers, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (c) Select the expression for the time-dependent emf induced in the loop based on the expression you entered in part (а).В. SchematicChoice : E = 2n² fr² B sin(27f) E= 2n² fr²B cos(27f) E = ar² B cos(27 ft) E = 2n² fr² B cos(2rft) E = 2n² fr²B sin(2n ft) = ar²B sin(27 ft) Part (d) Calculate the induced emf in the loop, in volts, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. Part (e) Select the expression for the induced current in the loop based on the expression you entered in part (c). SchematicChoice : 4n f2r³B 473 f²r³B - sin(27 ft) I = cos(27 ft) I= R sin(27 f) I = R I = 2n² fr² B sin(27f) I= 2n² fr² B sin(2rft) 27² fr²B I 2E ) sin(27 ft) R Part (f) Find the induced current in the loop, in amperes, at time t = 0.102 s. Numeric : A numeric value is expected and not an expression. I =
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