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A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.72 mm the values of elastic modulus for steel is 223 MPa. Take H1 = 7 cm, H2 = 10 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P =  ii) Stress-induced in the top bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.72 mm the values of elastic modulus for steel is 223 MPa. Take H1 = 7 cm, H2 = 10 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P =  ii) Stress-induced in the top bar =

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.72 mm the values of elastic modulus for steel is 223 MPa. Take H1 = 7 cm, H2 = 10 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar.

i) Magnitude Force, P = 

ii) Stress-induced in the top bar = 

iii) Stress-induced in the bottom bar = 

R cm x Rcm Steel bar H1 cm Q cm x Q cm Šteel bar H2 cm
Transcribed Image Text:R cm x Rcm Steel bar H1 cm Q cm x Q cm Šteel bar H2 cm
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