A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.47 mm the values of elastic modulus for steel is 211 MPa. Take H, = 4 cm, H2 = 11 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. Solution: R Cm X RCm Steel bar i) Magnitude Force, P = Hi cm ii) Stress-induced in the top bar = Q cm x Qcm Steel bar Hz cm iii) Stress-induced in the bottom bar =

A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.47 mm the values of elastic modulus for steel is 211 MPa. Take H, = 4 cm, H2 = 11 cm, top bar (R) is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. Solution: R Cm X RCm Steel bar i) Magnitude Force, P = Hi cm ii) Stress-induced in the top bar = Q cm x Qcm Steel bar Hz cm iii) Stress-induced in the bottom bar =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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