A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.71 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 5 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 5 x 5 cm. Also, determine the stress-induced in each section of the bar. Solution: R CM X R Cm i) Magnitude Force, P = Steel bar H1 cm ii) Stress-induced in the top bar = Q cm x Qcm Šteel bar H2 cm iii) Stress-induced in the bottom bar =

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Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.