A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that theirsatisfaction rating is 80%. Jennie, a food critic, would like to test this. She takes a sample of 140 patrons, and gets a 77.7% sample satisfaction rating.(a) Create a 95% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773.Round your answers to four decimal places, if needed.)(b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 80%?O Since the interval does not contain 80%, Jennie should reject the null hypothesis at a = 0.05.O Since the interval contains 80%, Jennie should reject the null hypothesis at a = 0.05.O Since the interval does not contain 80%, Jennie should not reject the null hypothesis at a = 0.05.Since the interval contains 80%, Jennie should not reject the null hypothesis at a = 0.05.

From the provided information, Sample size (n) = 140 Sample proportion (p̂) = 0.777

Answered: A local five-star restaurant asks its…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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