A report shows that 47% of residents in a certain country surveyed in 2016 got their news from local television. A similar survey conducted in 2017 found that 37% of residents in the same country got their news from local television. Assume the sample size for each poll was 1100. Complete parts (a) and (b) below. a. Construct the 95% confidence interval for the difference in the proportions of residents in the country who get their news from local television in 2016 and 2017. First check that the conditions for using a two-proportion confidence interval hold. You can assume that the sample is a random sample. The Random and Independent condition The Large Samples condition The Big Populations condition The Independent Samples condition reasonably be assumed to hold. The 95% confidence interval for the difference (2016 minus 2017) is (.). (Round to three decimal places as needed.) b. Based on your interval, do you think there has been a change in the proportion of residents in the country who get their news from local television? Explain. that the difference in is between the lower and upper boundaries of the confidence interval. The interval 0, suggesting that it plausible that the proportions are the same. Since the boundary values television in 2016 than in 2017. we proportion of residents got their news from local

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