A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a sample of 129 patrons, and gets a 79.1% sample satisfaction rating. (a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%? O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.
A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a sample of 129 patrons, and gets a 79.1% sample satisfaction rating. (a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%? O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2. O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their
meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a
sample of 129 patrons, and gets a 79.1% sample satisfaction rating.
(a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not
percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.)
(b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%?
O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F650192d1-d2bd-4507-bb57-c42486ecf22d%2F021b093c-3ca3-4b0d-9235-c13e4d51c395%2Fd75bptn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their
meal, and the restaurant claims that their satisfaction rating is 84%. Jennie, a food critic, would like to test this. She takes a
sample of 129 patrons, and gets a 79.1% sample satisfaction rating.
(a) Create an 80% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not
percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.)
(b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 84%?
O Since the interval contains 84%, Jennie should reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval contains 84%, Jennie should not reject the null hypothesis at a = 0.2.
O Since the interval does not contain 84%, Jennie should reject the null hypothesis at a = 0.2.
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