A hospital is testing patients for a certain disease. If a patient has the disease, the test is designed to return a "positive" result. If a patient does not have the disease, the test should return a "negative" result. No test is perfect though. 99% of patients who have the disease will test positive. 5% of patients who don't have the disease will also test positive. 10% of the population in question has the disease. If a random patient tests positive, what is the probability that they have the disease? Round to the nearest whole percentage and divide the percentage by 3.
A hospital is testing patients for a certain disease. If a patient has the disease, the test is designed to return a "positive" result. If a patient does not have the disease, the test should return a "negative" result. No test is perfect though. 99% of patients who have the disease will test positive. 5% of patients who don't have the disease will also test positive. 10% of the population in question has the disease. If a random patient tests positive, what is the probability that they have the disease? Round to the nearest whole percentage and divide the percentage by 3.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
A hospital is testing patients for a certain disease. If a patient has the disease, the test is designed to return a "positive" result. If a patient does not have the disease, the test should return a "negative" result. No test is perfect though.
- 99% of patients who have the disease will test positive.
- 5% of patients who don't have the disease will also test positive.
- 10% of the population in question has the disease.
If a random patient tests positive, what is the probability that they have the disease? Round to the nearest whole percentage and divide the percentage by 3.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Recommended textbooks for you

A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON


A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
