In the state of Kentucky, there are 228 eight year olds diagnosed with ASD out of 18,462 eight year olds evaluated. In the state of Maine, there are 47 eight year olds diagnosed with ASD out of 2,197 eight year olds evaluated. Is there enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is more than the proportion in Maine? Test at the 5% level. State the hypotheses. Ho: P₁? P2 Ha: P1? P2 Calculate the test statistics. Round to four decimal places. P₁ = P2 = Calculate the standardized test statistic. Round three decimal places. Z = Find the p-value. Round to four decimal places. p-value = State your decision. 0° Since the p-value is greater than .05, fail to reject Ho. O Since the p-value is less than .05, fail to reject Ho. O Since the p-value is greater than .05, reject Ho. O Since the p-value is less than .05, reject Ho. Interpret the results.

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In the state of Kentucky, there are 228 eight year olds diagnosed with ASD out of 18,462 eight year olds
evaluated. In the state of Maine, there are 47 eight year olds diagnosed with ASD out of 2,197 eight year
olds evaluated. Is there enough evidence to show that the proportion of children diagnosed with ASD in
Kentucky is more than the proportion in Maine? Test at the 5% level.
State the hypotheses.
Ho: P₁?
P2
Ha: P1? P2
Calculate the test statistics. Round to four decimal places.
P₁ =
P2
=
Calculate the standardized test statistic. Round three decimal places.
Z =
Find the p-value. Round to four decimal places.
p-value =
State your decision.
Since the p-value is greater than .05, fail to reject Ho.
O Since the p-value is less than .05, fail to reject Ho.
O Since the p-value is greater than .05, reject Ho.
Since the p-value is less than .05, reject Ho.
Interpret the results.
O At the 5% level of significance, there is enough evidence to show that the proportion of children
liagnosed with ASD in Kentucky is less than the oport in Maine.
At the 5% level of significance, there is not enough evidence to show that the proportion of children
diagnosed with ASD in Kentucky is more than the proportion in Maine.
O At the 5% level of significance, there is not enough evidence to show that the proportion of children
diagnosed with ASD in Kentucky is not equal to the proportion in Maine.
O At the 5% level of significance, there is not enough evidence to show that the proportion of children
diagnosed with ASD in Kentucky is less than the proportion in Maine.
O At the 5% level of significance, there is enough evidence to show that the proportion of children
diagnosed with ASD in Kentucky is more than the proportion in Maine.
O At the 5% level of significance, there is enough evidence to show that the proportion of children
diagnosed with ASD in Kentucky is not equal to the proportion in Maine.
Transcribed Image Text:In the state of Kentucky, there are 228 eight year olds diagnosed with ASD out of 18,462 eight year olds evaluated. In the state of Maine, there are 47 eight year olds diagnosed with ASD out of 2,197 eight year olds evaluated. Is there enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is more than the proportion in Maine? Test at the 5% level. State the hypotheses. Ho: P₁? P2 Ha: P1? P2 Calculate the test statistics. Round to four decimal places. P₁ = P2 = Calculate the standardized test statistic. Round three decimal places. Z = Find the p-value. Round to four decimal places. p-value = State your decision. Since the p-value is greater than .05, fail to reject Ho. O Since the p-value is less than .05, fail to reject Ho. O Since the p-value is greater than .05, reject Ho. Since the p-value is less than .05, reject Ho. Interpret the results. O At the 5% level of significance, there is enough evidence to show that the proportion of children liagnosed with ASD in Kentucky is less than the oport in Maine. At the 5% level of significance, there is not enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is more than the proportion in Maine. O At the 5% level of significance, there is not enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is not equal to the proportion in Maine. O At the 5% level of significance, there is not enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is less than the proportion in Maine. O At the 5% level of significance, there is enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is more than the proportion in Maine. O At the 5% level of significance, there is enough evidence to show that the proportion of children diagnosed with ASD in Kentucky is not equal to the proportion in Maine.
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