A fitness course claims that it can improve an individual's physical ability. To test the effect of a physical fitness course on one's physical ability, the number of sit-ups that a person could do in one minute, both before and after the course, was recorded. Ten individuals are randomly selected to participate in the course. The results are displayed in the following table. Can it be concluded, from the data, that participation in the physical fitness course resulted in significant improvement? Let d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course)d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course). Use a significance level of α=0.05 for the test. Assume that the numbers of sit-ups are normally distributed for the population both before and after taking the fitness course. Sit-ups before 42 42 23 32 30 42 25 47 35 38 Sit-ups after 57 48 29 41 36 57 40 51 41 40 Step 5 of 5: Draw a conclusion for the hypothesis test. 1. Reject the null hypothesis. There is sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim. 2. Reject the null hypothesis. There is not sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim. 3. Fail to Reject the null hypothesis. There is sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim. 4.Fail to Reject the null hypothesis. There is not sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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A fitness course claims that it can improve an individual's physical ability. To test the effect of a physical fitness course on one's physical ability, the number of sit-ups that a person could do in one minute, both before and after the course, was recorded. Ten individuals are randomly selected to participate in the course. The results are displayed in the following table. Can it be concluded, from the data, that participation in the physical fitness course resulted in significant improvement?

Let d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course)d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course). Use a significance level of α=0.05 for the test. Assume that the numbers of sit-ups are normally distributed for the population both before and after taking the fitness course.

Sit-ups before	42	42	23	32	30	42	25	47	35	38
Sit-ups after	57	48	29	41	36	57	40	51	41	40

Step 5 of 5: Draw a conclusion for the hypothesis test.

1. Reject the null hypothesis. There is sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim.

2. Reject the null hypothesis. There is not sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim.

3. Fail to Reject the null hypothesis. There is sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim.

4.Fail to Reject the null hypothesis. There is not sufficient evidence, at the 0.05 level of significance, to support the fitness course's claim.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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