who do not pass the test is also employed. Training is successfully completed by only 50%of this group.if no pre Emplo
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Your company uses a pre employment of the test to screen applicants for the job of repairman.the test is passed by 60%of the applicants.Among those who pass the test 80% complete training successfully. In an experiment,a random sample of applicant who do not pass the test is also employed. Training is successfully completed by only 50%of this group.if no pre Employment test is used,what percentage of applicants would you expect to complete training successfully?
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- In a study assessing helping behavior among college students on their way to class, you recruit 10 students. You tell some participants that they are late for class and need to rush. You tell others they are right on time. Finally, you tell others they have lots of time before class. As they walk across campus, they come across a man (actually a confederate) who appears to need help. You measure the extent to which the participant noticed that the confederate needed help (1 = did not notice to 9 = really noticed). What is the acceptable level of risk? P >.05 p <.05 P = .05 P <.1The first test a doctor would order to determine whether a person is infected with HIV (the virus that causes AIDS) is the ELISA test. It detects antibodies and antigens for HIV. A study in Statistical Science by J. Gastwirth estimated that, if the person is actually infected with HIV, this test produces a positive result 97.7% of the time. If a person is not infected with HIV, the test result is negative 92.6% of the time. According the the US Centers for Disease Control (CDC), an estimated 1.1 million Americans out of a population of 321 million were infected with HIV in 2015. Using the information above, determine the probability that a randomly selected person whose ELISA test is positive actually is infected with HIV? a. What is the probability that a randomly selected American is infected with HIV? b. Using the answer to part (a) and the conditional probabilities of positive and negative ELISA test results, fill out the contingency table below: ELISA Test Result…Many fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by email is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.5% of those who received and opened an email request for a donation and 7.2% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (email or text message) and suppose that the given percentages are based on sample sizes of 2,000 (the actual sample sizes in the experiment were much larger). (Let p1 be the proportion who make a donation after receiving an email, and p2 be the proportion who make a donation after receiving a text message.)
- A crossover trail is a type of experiment used to compare two drugs. Subjects take one drug for a period of time, then switch to the other. The responses of the subjects are then compared using matched pair methods. In an experiment to compare two pain relievers, seven subjects took one pain reliever for two weeks, then switched to the other. They rated their pain level from 1 to 10, with larger numbers representing higher levels of pain. The results are listed below. Can you conclude that the mean pain level is more with drug B? Use the 0.05 level and the p- values method.An ecology class used binoculars to watch 23 turtles at Walden Pond. It was found that 18 were box turtles and 5 were snapping turtles. What kind of study is this? -observational -census -simulation -experimentalIn the Star and Tribune newspaper, there is an article entitled “1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. We take a sample of 200 buses and find that 20 buses fail the safety inspection. If we construct a 95% confidence interval estimate for the true proportion of all Minnesota school buses that fail the safety tests, what is the upper limit of the interval? (Enter you answer including 3 decimal positions, e.g. .234)
- In Class Exercise You are asked to evaluate the effect of a fast acting blood pressure medication. You take a random sample of 200 people from the population and assign half of them at random to take the pill. Of the 100 you told to take the pil| 25 refuse and 75 take it. At the end of a week you check the blood pressure of the group assigned to get the pill and it is 120 on average and the blood pressure of the group assigned to control is 127.5 on average. 1. What is Y;, what is Z;, what is D;? 2. What is the first stage? Estimate and interpret 3. What is the reduced form? Estimate and interpret. 4. What is the effect of the drug on blood pressure?A researcher wants to see if police officers’ enthusiasm for their jobs changes after having endured a horrific event (such as killing someone or being shot). She tests a group of officers who have endured such an event and another group that has not on a measure of job satisfaction. What test should she run? Is it one-tailed or two-tailed test?A statistics student at Pleasantville High School (PHS) looked at seat belt use by drivers. Customers were observed driving into a local convenience store. After the drivers left their cars, the student asked each driver several questions about seat belt use. In all, 80% of the drivers said that they always use seat belts. However, the student observed that only 61.5% of these same drivers were actually wearing a seat belt when they pulled into the store parking lot. Which of the following best explains the difference in the two percentages? (A) The difference is due to sampling variability. We shouldn't expect the results of a sample to match the truth about the population every time. (B) The difference is due to response bias. Drivers who don't use seat belts are likely to lie and say they do use seat belts. (C) The difference is due to undercoverage bias. The study included only customers of the convenience store and did not include all drivers in the population. (D) The difference…
- A drug company claims that an allergy medication causes headaches in 5% of those who take it. A medical researcher believes that more than 5% of those who take the drug actually get headaches. Identify the population(s). 5% of those who take the drug actually get headaches. the proportion of those who take the drug who get a headache. all individuals who take the medication. more than 5% of those who take the drug actually get headaches. What is the variable being examined for individuals in the population(s)? more than 5% of those who take the drug actually get headaches. the proportion of those who take the drug who get a headache. whether or not a person who takes the drug gets a headache. 5% of those who take the drug actually get headaches.Many fundraisers ask for donations using email and text messages. A paper describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by email is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, 1.7% of those who received and opened an email request for a donation and 7.8% of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (email or text message) and suppose that the given percentages are based on sample sizes of 2,000 (the actual sample sizes in the experiment were much larger). (Let p1 be the proportion who make a donation after receiving an email, and p2 be the proportion who make a donation after receiving a text message.) Find the test statistic and P-value. (Use a table or SALT. Round your test statistic to two…You are a sales manager for a grocery store, and you want to see if the introduction of a new sales promotion will increase the sales in your store. To do so, you decided to create an experiment by giving a small sample of customers the promotion before expanding it to a larger customer base. You gave 18 people the promotion, and also observed the sales of 27 people who did not get the promotion as a control group. You found those who received the promotion to have an average monthly sales of $456.60, with a sample standard deviation of $52.23. You found those who did not receive the promotion had an average monthly sales of $361.46, with a sample standard deviation of $56.11. Suppose you want to use hypothesis testing (two-sample test) to investigate if the promotion has increased the sales of your store. Using the order promotion no promotion in your hypothesis test, what is the value of the test statistic for your analysis? Note: 1- Only round your final answer. Round your final…