A horizontal curve is designed with a '500' m radius. The curve has a tangent length of 120 m and the Pl is at station 3 + 140. Determine the stationing of the PT. a. Station of PT= 3 + 255.53 b. Station of PT= 3 + 257.09 C. Station of PT= 3 + 256.99 d. Station of PT= 3 + 256.74 e. Station of PT= 3 + 257.80

A horizontal curve is designed with a '500' m radius. The curve has a tangent length of 120 m and the Pl is at station 3 + 140. Determine the stationing of the PT. a. Station of PT= 3 + 255.53 b. Station of PT= 3 + 257.09 C. Station of PT= 3 + 256.99 d. Station of PT= 3 + 256.74 e. Station of PT= 3 + 257.80

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Problem 1 A simple curve connects two tangents AB and BC with bearings N 75°12' E and S 78°36' E, respectively. If the stationing of P.C. is 10+185.28. and its middle ordinate is 7.46 m, Determine the following: a. Radius of the curve. b. Tangent Distance C. External Distance Long Chord. d. e. Length of the curve. f. Stationing of the vertex g. Degree of the curve using Arc Basis
The common tangent BC of a reversed curve with a common radius is 280.5 and has azimuth of 312deg 29’. AB is a tangent of the first curve whose azimuth is 252deg 45’. CD is a tangent of the second curve whose azimuth is 218deg 13’. PI1 is at station 16 + 523.37. A is at PC and D is at PT. Find the stationing of PI2. a. 16 + 785.88 b. 16 + 883.4 c. 17 + 051.8 d. 16 + 685.11
Show solution w/fbd
1. The curve of a diversion road has a tangent “AB” which is directed due North and theother tangent “BC” is having a bearing of ?70°?. Point “A” is located at P.C. whosestationing is 12 + 600. The degree of curve using arc-basis is 5°.a. Compute the radius of the curve.b. Compute the long chord of the curve.c. What is the stationing at P.I.?d. Compute for the middle ordinate.e. Compute for the external distance.
Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' %3D R1 = 250 m. T1 = 215 m. Sta PI = 1 +376.50 Find I, R2, and T2 and stationing of the PC, PCC, and PT. ANSWERS: | = 91° 20' R2 = 150.33 m. T2 = 174.46 m. LC = 163.62 m. LC2 = 141.24 m.
Two tangent of a simple curve have azimuths of 248°15' and 294°30' are connected by a 4.2° curve. If sta. V is at 7 + 196.25, compute the other elements of the curve. a. The radius of the curve. b. The external distance of the curve. C. The middle ordinate of the curve.
PROBLEM 22: The common tangent BC of a reversed curve is 300 m and has a bearing of S35°E. AB is tangent of the first curve whose bearing is N70°E. CD is tangent of the second curve whose bearing is N54°E. A is at P.C. while D is at the P.T. The radius of the first curve is 220 m. P.li is at 8 + 523.5. Find the stationing of the P.T. a. 8+ 564.67 b. 8 + 847.42 c. 8+ 823.45 d. 8 + 934.45
The common tangent of a compound curve has a length of 70 m. This common tangent makes an angle of 14° and 20° to the tangents of the compound curve respectively. If T1 = 40 m, determine: a. The radius of the second curve. b. The radius of the first curve. c. The station of PT if PC is at 29+999.99 Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
Sta. PT of a compound curve is at 15 +480, 1₁-30°, 12-36°, D₁-4°, D₂=5° a. What is the sta. of the vertex of the compound curve ? b. Determine the long chord of the compound curve.
A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively. The length of the chord is 340m long measured from the P.C to the P.T of the curve and is parallel to the common tangent having an azimuth 270 °. If the stationing of P.T is 6+000 a) Plot the compound curve b) Compute all of the elements of a compound Curve. c) Determine the stationing by the interval of 20 of the curve
The central angles of a compound curve are 30° and 40° respectively. In addition, the degrees of the curves are 6° and 4° respectively. PI is at 5+01. a. What is the length of the common tangent? b. What is the station of PCC? c. What is the station of PT? Draw and plot the curve. Compute all of the necessary elements of the curve. Include the proper units/dimensions and round-off the answers to 3 decimal places.
Situation No. 3 Solve and Give the complete solutions.