Given the following elements of the compound curve shown:h = 37° 30'I2 = 53° 50'%3DR1 = 250 m.T1 = 215 m.Sta PI = 1 +376.50Find I, R2, and T2 and stationing of the PC, PCC, and PT.ANSWERS:| = 91° 20'R2 = 150.33 m.T2 = 174.46 m.LC = 163.62 m.LC2= 141.24 m.

Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' R1 = 250 m. %3D T1 = 215 m. Sta PI = 1+376.50 Find I, R2, and T2 and stationing of the PC, PCC, and PT. ANSWERS: = 91° 20' R2 = 150.33 m. %3D T2 = 174.46 m. LC = 163.62 m. %3D LC2 = 141.24 m.

Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' R1 = 250 m. %3D T1 = 215 m. Sta PI = 1+376.50 Find I, R2, and T2 and stationing of the PC, PCC, and PT. ANSWERS: = 91° 20' R2 = 150.33 m. %3D T2 = 174.46 m. LC = 163.62 m. %3D LC2 = 141.24 m.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.

Question

Given the following elements of the compound curve shown:
h = 37° 30'
I2 = 53° 50'
%3D
R1 = 250 m.
T1 = 215 m.
Sta PI = 1 +376.50
Find I, R2, and T2 and stationing of the PC, PCC, and PT.
ANSWERS:
| = 91° 20'
R2 = 150.33 m.
T2 = 174.46 m.
LC = 163.62 m.
LC2
= 141.24 m.

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