If d is the distance between equidistant odd ordinates, the Simpson's rule for the areas, * is d/3[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4 + ... + hn - 1)] [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4ppp + ... + hn - 1)] d/2[h1 + hn x 2(h2 + h4 + .. + hn - 1) + 4(h3 + h5 + + hn - 2)] ... d/6 [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4 + + hn - 1)] ...
If d is the distance between equidistant odd ordinates, the Simpson's rule for the areas, * is d/3[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4 + ... + hn - 1)] [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4ppp + ... + hn - 1)] d/2[h1 + hn x 2(h2 + h4 + .. + hn - 1) + 4(h3 + h5 + + hn - 2)] ... d/6 [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 + h4 + + hn - 1)] ...
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![If d is the distance between equidistant odd
ordinates, the Simpson's rule for the areas,
* is
d/3[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2
+ h4 + ... + hn - 1)]
[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 +
h4ppp + ... + hn - 1)]
d/2[h1 + hn x 2(h2 + h4 + .. + hn - 1) + 4(h3
+ h5 + ... + hn - 2)]
d/6 [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2
+ h4 + ... + hn - 1)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27a6c806-92c8-4afc-afd1-80167576208a%2F8a5b69ae-d4e5-47c2-9baf-338fd7d57f64%2Flgtj4dgn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If d is the distance between equidistant odd
ordinates, the Simpson's rule for the areas,
* is
d/3[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2
+ h4 + ... + hn - 1)]
[h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2 +
h4ppp + ... + hn - 1)]
d/2[h1 + hn x 2(h2 + h4 + .. + hn - 1) + 4(h3
+ h5 + ... + hn - 2)]
d/6 [h1 + hn + 2(h3 + h5 + ... + hn - 2) + 4(h2
+ h4 + ... + hn - 1)]
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