The door shown provides outdoors access to the basement of a building. The door has hinges at points B, C, and D, and it weighs 80 lb with center of gravity at point G. The force Facts perpendicular to the door. If F = 50 lb, determine the resultant moment of Fand the 80 lb weight about line BCD. Figure P4.48 A (34, 15,5) in. B (58,5,28) in. C (34,15,28) in. D(10,30,28) in. G (34,15, 16) in. (F C G
The door shown provides outdoors access to the basement of a building. The door has hinges at points B, C, and D, and it weighs 80 lb with center of gravity at point G. The force Facts perpendicular to the door. If F = 50 lb, determine the resultant moment of Fand the 80 lb weight about line BCD. Figure P4.48 A (34, 15,5) in. B (58,5,28) in. C (34,15,28) in. D(10,30,28) in. G (34,15, 16) in. (F C G
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The door shown provides outdoors access to the basement of a building. The door has hinges at
points B, C, and D, and it weighs 80 lb with center of gravity at point G. The force Facts
perpendicular to the door.
If F= 50 lb, determine the resultant moment of Fand the 80 Ib weight about line BCD.
Figure P4.48
A (34,15,5) in.
B (58,5,28) in.
C (34,15,28) in.
D(10,30,28) in.
G(34, 15, 16) in.
(F
![Calculate the unit vector along segment BCD using endpoints B and D.
(10– 58)î +(30–5) }+(28– 28)k
(10– 58)* +(30– 5)* +(28– 28)*
-48
25
48² + 25²
V48? +25?
=[-0.8869i +0.4619 ]
Obtain the unit vector in the direction of force vector by switching i and j components and
taking off the negative sign.
ûp =[0.4619î + 0.8869;]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f92bd90-fd8b-43e4-b205-e3a11c7fb824%2F017f9d22-b4d8-4eb3-b982-b65ab60e262c%2Favam0hi_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the unit vector along segment BCD using endpoints B and D.
(10– 58)î +(30–5) }+(28– 28)k
(10– 58)* +(30– 5)* +(28– 28)*
-48
25
48² + 25²
V48? +25?
=[-0.8869i +0.4619 ]
Obtain the unit vector in the direction of force vector by switching i and j components and
taking off the negative sign.
ûp =[0.4619î + 0.8869;]
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