PROBLEM 22: The common tangent BC of a reversed curve is 300 m and has a bearing of S35°E. AB is tangent of the first curve whose bearing is N70°E. CD is tangent of the second curve whose bearing is N54°E. A is at P.C. while D is at the P.T. The radius of the first curve is 220 m. P.lı is at 8 + 523.5. Find the stationing of the P.T. a. 8+ 564.67 b. 8+ 847.42 c. 8+ 823.45 d. 8+ 934.45
PROBLEM 22: The common tangent BC of a reversed curve is 300 m and has a bearing of S35°E. AB is tangent of the first curve whose bearing is N70°E. CD is tangent of the second curve whose bearing is N54°E. A is at P.C. while D is at the P.T. The radius of the first curve is 220 m. P.lı is at 8 + 523.5. Find the stationing of the P.T. a. 8+ 564.67 b. 8+ 847.42 c. 8+ 823.45 d. 8+ 934.45
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![PROBLEM 22: The common tangent BC of a
reversed curve is 300 m and has a bearing of
S35°E. AB is tangent of the first curve whose
bearing is N70°E. CD is tangent of the second
curve whose bearing is N54°E. A is at P.C.
while D is at the P.T. The radius of the first
curve is 220 m. P.li is at 8 + 523.5. Find the
stationing of the P.T.
a. 8+ 564.67
b. 8 + 847.42
c. 8+ 823.45
d. 8 + 934.45](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd323d4d0-54d1-42a1-8c1d-58779e03a477%2F9bac32fe-d35d-4583-b1b1-f83adff84818%2F0d0vhe_processed.png&w=3840&q=75)
Transcribed Image Text:PROBLEM 22: The common tangent BC of a
reversed curve is 300 m and has a bearing of
S35°E. AB is tangent of the first curve whose
bearing is N70°E. CD is tangent of the second
curve whose bearing is N54°E. A is at P.C.
while D is at the P.T. The radius of the first
curve is 220 m. P.li is at 8 + 523.5. Find the
stationing of the P.T.
a. 8+ 564.67
b. 8 + 847.42
c. 8+ 823.45
d. 8 + 934.45
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