A 4-degree simple curve have tangents with bearings of N 20 ̊ E and N 60 ̊ E, respectively. The stationing of PI is 3 + 980. Determine the middle ordinate in meters. Determine the stationing of PT. Determine the stationing of a point Q on the curve whose deflection angle from P

Q: The line connecting the PC and PT of the simple curve is 120.4m. The radius is 213.6m. If the…

A:

Q: EI is constant (Assume EI = 1 kN-m2). Solve using the moment-area method. Determine the angle in…

A: Given: Required: angle in radians between the tangents at A and tangent at B. angle in radians…

Q: Given the following, solve for the radius of the curve: M = 25.988m | = 54.939° ●

A: Given Mid ordinate value (M) =25.988 m Angle (I)= 54.9390  To find  Radius of curve (R) Formula used…

Q: Solve for the layout of the giren reverse Curve by deflection method with the given elements D. - 5°…

A:

Q: If the length of the parabolic curve is 10 meters, Point PI is 5 meters away from Point PC,…

A: True. The point of intersection is always at the half length of parabolic curve

Q: Problem 7. 7.Station PT of the compound curve is at 15 + 480.14. I, = 30°, I2 = 36°, D1 = 4°, D2 =…

A: We know that ; D=1145.92R Can be written as  ; R2 = 1145.92D2 R2 = 1145.925 = 229.184 m

Q: 2. H.W.: Find the equation of tangent to the curve y =x+- at the point (1,3).

A: Here we have to find equation of tangent to curve

Q: Determine the location of PC and PT. Calculate the dimensions of the parts of our simple curve (use…

A: R=1718.87D=1718.873.5=573m

Q: Solve using moment area method

A: Given Data  EI = Constant  Determine the force 'P' required at C, if vertical deflection at C is to…

Q: The curve y= x* bounds the shaded 600 section on top. The vertical lines X = 2 in. and x = 5 in.…

A: Given Data: The equation of the curve is y=x4. The limit of curve in X-direction is 2 in. to 5 in.…

Q: Х a W C a B

A: Solution: Ay+By=waMA=0By×2a=wa×a2By=wa4Ay=3wa4

Q: STA PT = 24+342, determine STA PI

A:

Q: Determine the slope of the tangent line (in rad) at C and the deflection (in mm) at B using the…

A:

Q: EI is constant (Assume EI = 1 kN-m2). Solve using the moment-area method. Determine the angle in…

A: Given: To find: Determine the angle in radians between the tangents at A and tangent at B.…

Q: e= 120° (PI = 2020 m PC /PT D= 3.5°

A:

Q: 2. A circular curve has the following known elements: Middle Ordinate = 2 m Length of Long Chord =…

A:

Q: The given overhanging beam is loaded as shown. Use E = 1.5 x 10^6 psi and I= 40 in*4 180 Ib/ft 1350…

A:

Q: 47.5 CM 108° 54 108 47.5 CM

A:

Q: Given the following data: g1=+5% g2=-4% L=80m sta.PC=5+120 elev.PC=105.42m. Determine (a) sta. and…

A: The grade of upgrade, g1 = +5%The grade of downgrade, g2 =-4%Station of PC =5+120Elevation of PC,…

Q: The tangents of a simple curve have bearings of N. 20° E. and N. 80° E. respectively. The radius of…

A: E = R [ Sec(∆2) - 1 ] R = Radius = 200 m ∆ = 80 - 20 = 60° E = 200 [ Sec(602)-1 ] = 30.94 m

Q: What is the stationing of PC  if the stationing of PI = 042+089.6 based on the given elements of the…

A: Introduction-The Curves are commonly used in communication lines to ensure that the change in…

Q: Solve Problems by the moment-areamethod. EI is constant. Compute the slope at A and the…

A: For calculating slope at A and deflection at D in this question the following steps are shown. We…

Q: The deflection angle from PC of two points A and B on a simple curve are 3°15’ and 8°15’,…

A: Given data: Deflection angle PC to A = 3∘15' PC to B=8∘15' The chord distance between A and B is 40m

Q: The elements of a reverse curve are as follows: I1 = 18.1˚  I2 = 23.5˚  D1 = 2˚  D2 = 4.7˚  If…

A: Given : I1 = 18.1°I2 = 23.5°D1 = 2°D2 = 4.7°Station PT = 27 + 674

Q: A field is in the form of a triangle. If the true bearing of side AB is N48°15'E, AB = 15, BC = 12,…

A: True bearing of side AB =  N 48°15' EAB = 15,BC = 12, CA = 20, Find:a.) The corrected distance of…

Q: A compound horizontal curve is provided in the figure below. I1 = 72°00'". I2 = 58°00'. BC station…

A: A compound curve is given, with different radii R1 =500 ft and R2 = 750 ft The stationing of the…

Q: Solve using double integration method

A: Given data in question  Moment 120 kNm Span 12 m To find out  Deflection and slope at B and C

Q: nects two tangents AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E respectively. If…

A: Given:- AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E stationing of the Vertex is…

Q: Given the following elements of a circular curve: middle ordinate = 2 m; length of long chord = 70…

A: Middle ordinate = 2m Length of long chord = 70 m Degree of curve = ?

Q: 2. AB BC N 75°E S 65⁰ E ✓ 30⁰ E R₁ = 2R₂ * Determine 200m the length of the compound curve.

A:

Q: The elements of a compound curve are as follows: I1 = 19.7˚  I2 = 24˚  D1 = 2.7˚  D2 = 4.5˚  If…

A:

Q: EI is constant (Assume EI = 1 kN-m2). Solve using the moment-area method. Determine the deviation…

A: Given: Required: deviation under the load Y with respect to the tangent at B. deviation under the…

Q: 3. AB вс due East N 30° F CD dae east Determine the length of reverse curve if T₁ =70m and 1₂=110m

A: Given : T1 = 70m,  T2 = 110m From the drawing, we can find out angle I1 and I2. Find out the length…

Instruments for Surveying

Surveying is the practice that determines the relative three-dimensional positions of many different points on the earth’s surface. There are various instruments used in Surveying like Theodolites, Total station, Tripod stands, Plane table, etc. for measuring horizontal angle, vertical and sloping angle, which are very useful for giving accurate and precise measurement.