SITUATION 6: The length of common tangent of a compound horizontal curve is 630 m. Di = 3°, l = 50°, l2 = 35°. 15. Compute the radius of the second curve. a. 1523.12 m b. 1302.25 m c. 912.12 m d. 1433.18 m 16. Compute the length of the chord connecting PC and PT. a. 1861.45 m b. 1184.78 m c. 1764.14 m d. 1945.45 m 17. Compute the total length of curve. a. 1208.81 m b. 1887.4 m c. 1662.1 m d. 1631.8 m
SITUATION 6: The length of common tangent of a compound horizontal curve is 630 m. Di = 3°, l = 50°, l2 = 35°. 15. Compute the radius of the second curve. a. 1523.12 m b. 1302.25 m c. 912.12 m d. 1433.18 m 16. Compute the length of the chord connecting PC and PT. a. 1861.45 m b. 1184.78 m c. 1764.14 m d. 1945.45 m 17. Compute the total length of curve. a. 1208.81 m b. 1887.4 m c. 1662.1 m d. 1631.8 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![SITUATION 6: The length of common
tangent of a compound horizontal curve is
630 m. Di = 3°, lı = 50°, l2 = 35°.
15. Compute the radius of the second curve.
a. 1523.12 m
c. 912.12 m
b. 1302.25 m
d. 1433.18 m
16. Compute the length of the chord
connecting PC and PT.
a. 1861.45 m
b. 1184.78 m
c. 1764.14 m
d. 1945.45 m
17. Compute the total length of curve.
a. 1208.81 m
c. 1662.1 m
d. 1631.8 m
b. 1887.4 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd323d4d0-54d1-42a1-8c1d-58779e03a477%2F5f31c8f8-27bd-4ed4-ae7f-ae9ca5136c87%2Fw115pvn_processed.png&w=3840&q=75)
Transcribed Image Text:SITUATION 6: The length of common
tangent of a compound horizontal curve is
630 m. Di = 3°, lı = 50°, l2 = 35°.
15. Compute the radius of the second curve.
a. 1523.12 m
c. 912.12 m
b. 1302.25 m
d. 1433.18 m
16. Compute the length of the chord
connecting PC and PT.
a. 1861.45 m
b. 1184.78 m
c. 1764.14 m
d. 1945.45 m
17. Compute the total length of curve.
a. 1208.81 m
c. 1662.1 m
d. 1631.8 m
b. 1887.4 m
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