nisKA genetic experiment involving peas yielded one sample of offspring consisting of 436 green peas and 120 yellow peas. Use a 0.01 significance level to test the claim that under thesame circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion thataddresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.@2WSWhat are the null and alternative hypotheses?OA. Ho: p=0.27H₁: p<0.27View an example82mmandOC. Ho: p*0.27H₁: p=0.27*HOE. Ho: p=0.27H₁: p>0.27XWhat is the test statistic?(Round to two decimal places as needed.)علی کو#3EDGet more help.80F3C$4RaFVQuestion Viewer%5TGB6MacBook AirYH&7N80UJ8MB. Ho: p=0.27H₁: p*0.27O D. Ho: P# 0.27H₁: p<0.27OF. Ho: p*0.27H₁: p>0.27PilIK(9H<IDDF9OLcommand)O>.4F10PI:;-optionClear allF11{[?1+="1ICheck answer45F12}]deletereturnshiftdrew

Suppose p is the population proportion of yellow peas.

Answered: A genetic experiment involving peas…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A genetic experiment involving peas yielded one sample of offspring consisting of 431 green peas and 162 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 25% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p#0.25 H: p 0.25 O E. Ho: p=0.25 H1: p>0.25 O F. Ho: p 0.25 H4:p=0.25 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value: %D (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. B. Reject the null hypothesis because the P-value is…
A genetic experiment involving peas yielded one sample of offspring consisting of 447 green peas and 124 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
A genetic experiment involving peas yielded one sample of offspring consisting of 423 green peas and 125 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p0.27 H₁: p 0.27 What is the test statistic? Z= (Round to two decimal places as needed.) What is the P-value? P-value= (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. C. Reject…
A genetic experiment involving peas yielded one sample of offspring consisting of 422 green peas and 122 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p= 0.26 H1: p>0.26 O B. Ho: p= 0.26 H,:p 0.26 H1: p= 0.26 What is the test statistic? (Round to two decimal places as needed.) St What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. B. Fail to reject the null hypothesis because the P-value is less than or…
Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon (mpg) than hybrid ones. Suppose that consumers test 254 hybrid sedans and get a mean of 26 mpg with a standard deviation of 4 mpg. Also, 237 non-hybrid sedans get a mean of 24 mpg with a standard deviation of 6 mpg. Suppose that both populations are known to be normal distributed. Conduct a hypothesis test to evaluate the manufacturers' claim. Test at a 4% level of significance. Let population 1 denote non-hybrids and population 2 denote hybrids. (a) H0 : μ1 ______ μ2 (b) Ha : μ1 _______ μ2 (c) In words, state what your random variable represents.The random variable is the (mean / difference in the / difference in the mean) miles per gallon of non-hybrid sedans and hybrid sedans.
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6971 subjects randomly selected from an online group involved with ears. There were 1319 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution.
A genetic experiment involving peas yielded one sample of offspring consisting of 435 green peas and 174 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p#0.26 В. Но: р30.26 H4:p= 0.26 H1:p>0.26 Ос. Но: р#0.26 O D. Ho: p#0.26 H1:p>0.26 H1: p<0.26 O E. Ho:p=0.26 O F. Ho: p= 0.26 H1: p<0.26 H4: p#0.26 What is the test statistic? z= (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? O A. Fail to reject the null hypothesis because the P-value is less than or equal to the…
A genetic experiment involving peas yielded one sample of offspring consisting of 431 green peas and 145 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p#0.26 O B. Ho: p#0.26 H:p>0.26 H:p=0.26 &c. Ho:p=0.26 O D. Ho: p= 0.26 H:p#0.26 H:p>0.26 O E. Ho: p=0.26 OF. Ho: p#0.26 H:p<0.26 H:p<0.26 What is the test statistic? (Round to two decimal places as needed.)
Small-business telephone users were surveyed 6 months after access to carriers other than Carrier A became available for wide-area telephone service. Of a random sample of 240 Carrier A users, 135 said they were attempting to learn more about their options, as did 227 of an independent random sample of 260 users of alternate carriers. Test, at the 1% significance level against a two-sided alternative, the null hypothesis that the two population proportions are the same. Click the link to view a standard normal distribution table. be the Let Px be the proportion of Carrier A users who said they were attempting to learn more about their options and Py proportion of users of alternate carriers who said they were attempting to learn more about their options. Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: Px-Py=0 H₁: Px-Py 20 O D. Ho: Px-P₁ #0 H₁: Px - Py = 0 B. Ho: Px-Py = 0 H₁: Px-Py 0
A genetic experiment involving peas yielded one sample of offspring consisting of 444 green peas and 126 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 23% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O A. Ho: p=0.23 O B. Ho: p=0.23 H₁: p>0.23 H₁: p=0.23 OC. Ho: p=0.23 O D. Ho: p=0.23 H₁: p0.23 H₁: p=0.23 What is the test statistic? Z= (Round to two decimal places as needed.) What is the P-value? P-value= (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because…
A genetic experiment involving peas yielded one sample of offspring consisting of 448 green peas and 155 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 25 % of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? A. Upper H 0 : p not equals 0.25 Upper H 1 : p less than 0.25 B. Upper H 0 : p not equals 0.25 Upper H 1 : p greater than 0.25 C. Upper H 0 : p equals 0.25 Upper H 1 : p not equals 0.25 Your answer is correct. D. Upper H 0 : p equals 0.25 Upper H 1 : p greater than 0.25 E. Upper H 0 : p equals 0.25 Upper H 1 : p less than 0.25 F. Upper H 0 : p not equals…
A genetic experiment involving peas yielded one sample of offspring consisting of 414 green peas and 133 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

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