A gas stream contains 40 mol% isopropanol in air and flows at 240 mol/min, 70°C, and 1 atm. You are to use a condenser operating at a lower temperature to liquefy and recover isopropanol for reuse in the process. (A) Assume the air dissolved in the liquid stream is negligible. If the condenser cool the gas stream to 25°C and produces a liquid condensate stream that is in equilibrium with the exiting gas stream, what is the mole percent recovery of isopropanol? (B) Now if you aim at recovering 98% of the isopropanol, at what temperature should the condenser operate? Still assume the air dissolved in the liquid stream is negligible. (C) Then you want to take into account of the impact of the air dissolved in the liquid stream on the isopropanol recovery. How does the isopropanol recovery at 25°C compare with the previous results in (A) if considering the air dissolved in the liquid stream? Fill in the code below to answer. % HW5.P1 % A gas stream contains 40 mol% isopropanol in air and flows at % 240 mol/min, 70C, and 1 atm. You are to use a condenser operating % at a lower temperature to liquefy and recover isopropanol for reuse in the process. % % Part (C): You want to take into account of the impact of the air dissolved % in the liquid stream on the isopropanol recovery. How does the isopropanol % recovery at 25C compare with the previous results in (A) % if considering the air dissolved in the liquid stream? % IPA vapor pressure at °25 C Psat = ________________________________________; % mm Hg % Henry's law constants at 25 °C (using Murphy Table B.5 *and* % assuming O2 and N2 solubility in IPA similar to water. Get % values at 25 °C by linear interpolation between 20 and 30 °C. HO2 = _____________; % mm Hg HN2 = _____________; % mm Hg % equations are nonlinear so use fsolve % vector of unknowns % 1 2 3 4 5 6 7 8 % x = [ yIPA yO2 yN2 n2 xIPA xO2 xN2 n3 ] F =@ (x) [ _______________________________; ... % IPA MB _____________________________________; ... % O2 MB _____________________________________; ... % N2 MB ____________________;... % IPA Raoult's ___________________;... % O2 Henry's ___________________;... % N2 Henry's ______________________;... % sum(y) = 1 ________________________]; % sum(x) = 1

A gas stream contains 40 mol% isopropanol in air and flows at 240 mol/min, 70°C, and 1 atm. You are to use a condenser operating at a lower temperature to liquefy and recover isopropanol for reuse in the process. (A) Assume the air dissolved in the liquid stream is negligible. If the condenser cool the gas stream to 25°C and produces a liquid condensate stream that is in equilibrium with the exiting gas stream, what is the mole percent recovery of isopropanol? (B) Now if you aim at recovering 98% of the isopropanol, at what temperature should the condenser operate? Still assume the air dissolved in the liquid stream is negligible. (C) Then you want to take into account of the impact of the air dissolved in the liquid stream on the isopropanol recovery. How does the isopropanol recovery at 25°C compare with the previous results in (A) if considering the air dissolved in the liquid stream? Fill in the code below to answer. % HW5.P1 % A gas stream contains 40 mol% isopropanol in air and flows at % 240 mol/min, 70C, and 1 atm. You are to use a condenser operating % at a lower temperature to liquefy and recover isopropanol for reuse in the process. % % Part (C): You want to take into account of the impact of the air dissolved % in the liquid stream on the isopropanol recovery. How does the isopropanol % recovery at 25C compare with the previous results in (A) % if considering the air dissolved in the liquid stream? % IPA vapor pressure at °25 C Psat = __________________________________; % mm Hg % Henry's law constants at 25 °C (using Murphy Table B.5 and % assuming O2 and N2 solubility in IPA similar to water. Get % values at 25 °C by linear interpolation between 20 and 30 °C. HO2 = _; % mm Hg HN2 = _; % mm Hg % equations are nonlinear so use fsolve % vector of unknowns % 1 2 3 4 5 6 7 8 % x = [ yIPA yO2 yN2 n2 xIPA xO2 xN2 n3 ] F =@ (x) [ _______; ... % IPA MB _; ... % O2 MB _________; ... % N2 MB ;... % IPA Raoult's _;... % O2 Henry's _;... % N2 Henry's ;... % sum(y) = 1 ____________]; % sum(x) = 1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

(A) Assume the air dissolved in the liquid stream is negligible. If the condenser cool the gas stream to 25°C and produces a liquid condensate stream that is in equilibrium with the exiting gas stream, what is the mole percent recovery of isopropanol?

(B) Now if you aim at recovering 98% of the isopropanol, at what temperature should the condenser operate? Still assume the air dissolved in the liquid stream is negligible.

(C) Then you want to take into account of the impact of the air dissolved in the liquid stream on the isopropanol recovery. How does the isopropanol recovery at 25°C compare with the previous results in (A) if considering the air dissolved in the liquid stream?

Fill in the code below to answer.

% HW5.P1

% A gas stream contains 40 mol% isopropanol in air and flows at

% 240 mol/min, 70C, and 1 atm. You are to use a condenser operating

% at a lower temperature to liquefy and recover isopropanol for reuse in the process.

% Part (C): You want to take into account of the impact of the air dissolved

% in the liquid stream on the isopropanol recovery. How does the isopropanol

% recovery at 25C compare with the previous results in (A)

% if considering the air dissolved in the liquid stream?

% IPA vapor pressure at °25 C

Psat = ________________________________________; % mm Hg

% Henry's law constants at 25 °C (using Murphy Table B.5 *and*

% assuming O2 and N2 solubility in IPA similar to water. Get

% values at 25 °C by linear interpolation between 20 and 30 °C.

HO2 = _____________; % mm Hg

HN2 = _____________; % mm Hg

% equations are nonlinear so use fsolve

% vector of unknowns

% 1 2 3 4 5 6 7 8

% x = [ yIPA yO2 yN2 n2 xIPA xO2 xN2 n3 ]

F =@ (x) [ _______________________________; ... % IPA MB

_____________________________________; ... % O2 MB

_____________________________________; ... % N2 MB

____________________;... % IPA Raoult's

___________________;... % O2 Henry's

___________________;... % N2 Henry's

______________________;... % sum(y) = 1

________________________]; % sum(x) = 1

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