Design a half-wave rectifier with a filter for the following conditions: a) The peak input
solve for the capacitor (Filter) values of the Half-wave
Design a half-wave rectifier with a filter for the following conditions:
a) The peak input voltage is 10 V. Input frequency is 60 Hz.
b)Use virtual diode (VON = 0.7 V).
c)The minimum output voltage should be at least 90% of the maximum output voltage.
d)The load resistance may vary from 1.5 k ohm to 2.5 k ohm.
Instructions:
~ Vomax = 10 - 0.7 = 9.3 V; Vomin = 0.9xVomax;
angleV = Vomax- Vomin
~ fin =60Hz; fp =60Hz.
~ Use the smallest value of load resistance (1.5 k ohm) to calculate the capacitor value.
~ Use the above calculated capacitor value (same value) to build 2 circuits (half-waverectifier with a filter), with load resistance of 1.5 kohm and 2.5 kohm, respectively.
~ Note: The same capacitor value is applied to the load resistance of 1.5 kohm and 2.5 kohm,respectively.
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