point(s) poSSIbleA frequency distribution is shown below. Complete parts (a) and (b).The number of televisions per household in a small townTelevisions1.Households304497261401(a) Use the frequency distribution to construct a probability distribution.P(x)12.3(Round to three decimal places as needed.)(b) Graph the probability distribution using a histogram. Choose the correct graph of the distribution below.OA.OB.Oc.AP(x)0.6-0.50.4-0.3AP(x)0.6-0.5-0.4-AP(x)0.6-0.50.40.3-0.2-0.3-0.2-0.2-0.1-0.1-0.1-# of Televisions#of Televisions#of TelevisionsDescribe the histogram's shape. Choose the correct answer below.CO symmetricO skewed right

Given : x(televisions) Frequency(fi)=Households frequency distribution is (Televisions)…

Answered: A frequency distribution is shown…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Step 2 Now, use the data in the table to make a histogram of the probability distribution. 1 2 3 4 or more P(x) 0.46 0.33 0.17 0.03 0.01 Recall that the height of each bar in a histogram indicates the class frequency. So to construct the histogram, put the x values on the horizontal axis and the probabilities on the vertical discrete, each class mark will be centered over the x value. There are five classes in the table, so there are axis. Since the data are 6. X vertical bars on the histogram. Select the histogram of the probability distribution. 0.5 0.5 0.4 0.4 0.3 0.3 0.2 0.2 0.1 0.1 1 4 or more 1 2 4 or more X 0.5 0.5 0.4 0.4 0.3 0.3 0.2 0.2 0.1 0.1 1 3 4 or more 1 2 3 4 or more Submit Skip (you cannot come back) (x)d (х)d 2. (x)d (х)d
A frequency distribution is shown below. Complete parts (a) and (b). The number of televisions per household in a small town Televisions 3 Households 21 445 722 1404 (b) Graph the probability distribution using a histogram. Choose the correct graph of the distribution below. O A. O B. c. APIO 0.64 05- AP) 0.6 05- 04- 0.3- 02 0.1- APD0 0.6- 0.5 04 0.3- 02- 0.1- 04 03- 02 0.1-
BOSTON COMMUTE TIME Refer to the accompanying frequency distribution. What problem would be created by using classes of 0–30, 30–60, . . . , 120–150?
Using the image answer the following. Find the probability that a randomly selected household in North America uses between 69 and 161 gallons of water per day. Show work
c. Age of first heart attack - The horizontal axis is age. The vertical axis is frequency (number of people who had their first heart attack at that age). The population is people in the US who have had at least one heart attack. Shape of distribution: uniform skewed left skewed right symmetric Justification:
A researcher surveys a sample of n = 20 college students and asks each person to identify their favorite movie. If the data were organized in a frequency distribution table, what would be included in the last column? G a list of movies K a list of students oa list of frequencies oa list of averages
Save The table shows population statistics for the ages of Best Actor and Best Supporting Actor winners at an awards ceremony. The distributions of the ages are approximately bell-shaped. Compare the z-scores for the actors in the following situation. Best Actor Best Supporting Actor p=53.0 p=43.0 o =6.4 o 15 In a particular year, the Best Actor was 27 years old and the Best Supporting Actor was 58 years old. 漸 Determine the z-scores for each. Best Actor z = -2.5 Best Supporting Actor: z = 0.33 (Round to two decimal places as needed.) s Interpret the z-scores. The Best Actor was more than 1 standard deviation above the mean, which is not unusual. The Best Supporting Actor was more than 1 standard deviation below the mean, which is not unusual. Help Me Solve This View an Example Get More Help- Clear All Check Answer 64°F search (8:
The graph shows the probability of cardiovascular disease by age and gender. Use the graph to find the probability that a randomly selected man between the ages of 25 and 34 Probability of Cardiovascular Disease 1- 0.9 0.8 a. has cardiovascular disease. Men b. does not have cardiovascular disease. 0.7 Women 0.6 0. 0.4 0.3 0.2- 0.14 20-24 25-34 35-44 45-54 55-64 65-74 75+ a. Use the graph to estimate the probability that a randomly selected man between the ages of 25 and 34 has cardiovascular disease. This probability is approximately (Type a decimal to two places.) Enter your answer in the answer box and then click Check Answer. 1 part remaining ClearAll CheckAnswer Copyright O 2021 Pearson Education Inc. All rights reserved. Terms of Use Privacy PolicyT Permissions Contact Us 76 F Mostly cloudy ere to search DELL
The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of 10. Suppose that one individual is randomly chosen. Let X = percent of fat calories. (a) Find the z-score corresponding to 43 percent of fat calories, rounded to 3 decimal places. (b) Find the probability that the percent of fat calories a person consumes is more than 43. (c) Shade the area corresponding to this probability in the graph below. (Hint: The x-axis is the z- score. Use your z-score from part (a), rounded to one decimal place). Shade: Left of a value Click and drag the arrows to adjust the values. -3 -- 3. -1.5 (d) Find the maximum number for the lower quarter of percent of fat calories. Round your answer to 3 decimal places. (e) Sketch the graph and write the probability statement. 2.
The athletic department asks 1000 students if they have been to a football game in the last year. The results indicate that 718 students said yes (Y), 151 said no (N), and 131 did not respond (NR).Use the information given above to make a relative frequency distribution showing the percentage of students in each of the three categories. (Round your answers to one decimal place.) Response Percentage Y % N % NR %
Using table 2, find the probability that an accident victim was from Connecticut and had no restraints on. Detail your answer using the lettering given, e.g., P (A or C) = ... Table 2: Relative Frequencies Table A B Restraints No Restraints C California 0.622 0.309 0.931 D Connecticut 0.042 0.026 0.069 0.664 0.336 1.000
Fifty-one (51) statistics students were asked how much sleep they get per school night (rounded to the nearest hour). The results are as shown in the following frequency distribution table. Find the median. State your result/answer as a value with exactly one digit after the decimal. Values Frequency CumulativeFrequency 4 2 2 5 5 7 6 7 14 7 11 25 10 16 41 11 6 47 12 4 51

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