### Distribution of Major HurricanesThe accompanying table provides a probability distribution for the number of major hurricanes, Y, for a randomly selected year between 1851 and 2012. Complete parts (a) and (b) below.#### Part (a)Find and interpret the mean of the random variable \( \mu \) = [Instructions here], rounding to three decimal places as needed.#### Distribution of Major Hurricanes| Y | P(Y=y) ||---|----------|| 0 | 0.1845 || 1 | 0.2383 || 2 | 0.2383 || 3 | 0.1684 || 4 | 0.0726 || 5 | 0.0307 || 6 | 0.0131 || 7 | 0.0051 || 8 | 0.0054 || 9 | 0.0054 |#### Instructions:1. Find the mean (μ) for the given probability distribution. Use the formula:\[ μ = \sum (Y \times P(Y=y)) \]2. Interpret the mean in the context of this distribution.#### Part (b)[Remainder of instructions and content for part (b)]For help solving the problem or viewing an example, see the "Help me solve this" or "View an example" options.### Additional Resources- Learning & Resources- Accessibility Resources- Communication ToolsRemember to click "Done" once you have completed the interpretation, and you can also use the "Print" option if needed.---**Note**: This text is for educational purposes, guiding users through calculating and interpreting the mean of a probability distribution. The table displayed is a distribution of major hurricanes based on the provided data.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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B12. (Excel: Calculating means, standard deviations, covariance, and correlation) Given the probability distributions of returns for stock X and stock Y, compute: a. the expected return for each stock, and b. the variance of the return for each stock c. the covariance between the returns for stock X and stock Y d. the correlation coefficient between the returns for stock X and stock Y. Probability Stock X Stock Y 0.1 -10% 4% 0.3 0 8 0.3 6 0 0.2 10 -5 0.1 20 15
The probability distribution of x, the number of defective tires on a randomly selected car checked at a certain inspection station is given in the following table. Fill in the missing value: X 0 1 2 3 4 probability 0.66 0.12 0.04 0.02
In the accompanying table, the random variable x represents the number of televisions in a household in a certain country. Determine whether or not the table is a probability distribution. If it is a probability distribution, find its mean and standard deviation.LOADING... Click the icon to view the data.Question content area bottomPart 1If the table is a probability distribution, what is its mean? Select the correct choice below and fill in any answer boxes within your choice.A.Its mean is enter your response here.(Round to the nearest tenth as needed.)B.The table is not a probability distribution.Part 2If the table is a probability distribution, what is its standard deviation? Select the correct choice below and fill in any answer boxes within your choice.A.Its standard deviation is enter your response here.(Round to the nearest tenth as needed.)B.The table is not a probability distribution.xP(x)00.0210.1720.2430.2540.1850.14
Find the mean, variance and standard deviation for the probability distribution given below: X -4 6 8 10 P(X) 0.57 0.111 0.21 0.109 A. Mean = B. Variance = C. Standard Deviation =
Find the mean of the following probability distribution? P(a) 0 0.1849 1 0.1895 2 0.0147 3 0.3983 4 0.2125 mean- (report answer rounded to one decimal place) Submit Question
The random variable X is the crew size of a randomly selected shuttle mission. Its probability distribution is shown below. Complete parts a through c. x 2 4 5 6 7 8 P(X=x) 0.034 0.022 0.353 0.190 0.395 0.006 a. Find and interpret the mean of the random variable. μ=_____ (Round to three decimal places as needed.) Interpret the mean. Select the correct choice below and fill in the answer box to complete your choice. A. The average number of persons in a shuttle crew is_____person(s). B. The most common number of persons in a shuttle crew is_____person(s). b. Obtain the standard deviation of the random variable. σ=______ (Round to three decimal places as needed.) c. Construct a probability histogram for the random variable; locate the mean; and show one-, two-, and three-standard-deviation intervals. Choose the correct histogram below. The mean is____.The one-standard-deviation interval…
Find the mean, variance and standard deviation for the probability distribution given below: X -2 5 11 8 P(X) 0.597 0.139 0.207 0.057 A. Mean = B. Variance = C. Standard Deviation =
Illustration #2: Let X be a random variable with the following probability distribution -4 P(X=x) 0.2 0.3 0.4 0.1 30. Find the mean and variance.
Mean St. Dev. Distribution Males 23.5 in. 1.1 in. Normal Females 22.7 in. 1.0 in. Normal Use the data in the table for sitting adult males and females. These data are used often in the design of different seats, including aircraft seats, train seats, theater seats, and classroom seats. Find the probability that a female has a back-to-knee length between 22.0 in and 24.0 in Warning! This question is not multiple choice! You are to fill in the blank with the correct answer. Write your answer in the form 0.1234
The number of needed repairs while under warranty for a Sure Cut lawnmower has a population distribution as shown in the probability histogram below. The population mean is also given. Population 0.6 - 0.5- 0.4- population mean: u=1.15 0.3- 0.2- Number of repairs Probability
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Use the table to the right, which shows the age distribution of those who earned less than minimum wage in a recent year. If a worker is randomly selected from those surveyed, what is the probability that the person is younger than 55? Age Working Below Minimum Wage (thousands) 16-19 348 20-24 416 25-34 305 35-44 175 45-54 132 55-64 47 65 and older 40 Question content area bottom Part 1 The probability that the person is younger than 55 is enter your response here . (Type a decimal rounded to three decimal places as needed.)

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