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A frequency distribution is shown below. Complete parts (a) and (b). The number of televisions per household in a small town Televisions 0 Households. 24 2 722 (a) Use the frequency distribution to construct a probability distribution. P(x) OA. X 0 1 2 3 (Round to three decimal places as needed.) (b) Graph the probability distribution using a histogram. Choose the correct graph of the distribution below. AP(X) 1 443 0.6- 0.5- 0.4- 0.3- 0.2 0.1- 0 1 2 3 x # of Televisions 3 1402 Q G Describe the histogram's shape. Choose the correct answer below. O B. AP(X) 0.6 0.5- 0.4- 0.3- 0.2 0.1- 0 1 2 3 # of Televisions Q 2 O C. AP(x) 0.6 0.5- 0.4- 0.3- 0.2- 0.1 # of Televisions Q

A frequency distribution is shown below. Complete parts (a) and (b). The number of televisions per household in a small town Televisions 0 Households. 24 2 722 (a) Use the frequency distribution to construct a probability distribution. P(x) OA. X 0 1 2 3 (Round to three decimal places as needed.) (b) Graph the probability distribution using a histogram. Choose the correct graph of the distribution below. AP(X) 1 443 0.6- 0.5- 0.4- 0.3- 0.2 0.1- 0 1 2 3 x # of Televisions 3 1402 Q G Describe the histogram's shape. Choose the correct answer below. O B. AP(X) 0.6 0.5- 0.4- 0.3- 0.2 0.1- 0 1 2 3 # of Televisions Q 2 O C. AP(x) 0.6 0.5- 0.4- 0.3- 0.2- 0.1 # of Televisions Q

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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### Frequency and Probability Distributions #### A. Frequency Distribution A frequency distribution is shown below. Complete parts (a) and (b). **The number of televisions per household in a small town:** | Televisions | 0 | 1 | 2 | 3 | |-------------|----|-----|-----|------| | Households | 24 | 443 | 722 | 1402 | #### (a) Probability Distribution Using the frequency distribution to construct a probability distribution: 1. Calculate the total number of households. - Total = 24 + 443 + 722 + 1402 = 2591 2. Compute the probability for each number of televisions (x): - P(0) = 24 / 2591 ≈ 0.009 - P(1) = 443 / 2591 ≈ 0.171 - P(2) = 722 / 2591 ≈ 0.279 - P(3) = 1402 / 2591 ≈ 0.541 3. The probability distribution is as follows: - x: 0 | P(x): 0.009 - x: 1 | P(x): 0.171 - x: 2 | P(x): 0.279 - x: 3 | P(x): 0.541 **(Round to three decimal places as needed.)** #### (b) Histogram Graph the probability distribution using a histogram. Choose the correct graph of the distribution below: - **Option A:** - Bars are at 0, 1, 2, and 3. - The heights are approximately 0.009, 0.171, 0.279, and 0.541 respectively. - **Option B:** - Bars are at 0, 1, 2, and 3. - The heights are different and don't match the calculated probabilities. - **Option C:** - Bars are at 0, 1, 2, and 3. - The heights decrease from 0 to 3, not matching the increasing values calculated. **Correct Answer: Option A** #### Histogram Shape Describe the histogram's shape. Choose the correct answer below: - **Skewed
Transcribed Image Text:### Frequency and Probability Distributions #### A. Frequency Distribution A frequency distribution is shown below. Complete parts (a) and (b). **The number of televisions per household in a small town:** | Televisions | 0 | 1 | 2 | 3 | |-------------|----|-----|-----|------| | Households | 24 | 443 | 722 | 1402 | #### (a) Probability Distribution Using the frequency distribution to construct a probability distribution: 1. Calculate the total number of households. - Total = 24 + 443 + 722 + 1402 = 2591 2. Compute the probability for each number of televisions (x): - P(0) = 24 / 2591 ≈ 0.009 - P(1) = 443 / 2591 ≈ 0.171 - P(2) = 722 / 2591 ≈ 0.279 - P(3) = 1402 / 2591 ≈ 0.541 3. The probability distribution is as follows: - x: 0 | P(x): 0.009 - x: 1 | P(x): 0.171 - x: 2 | P(x): 0.279 - x: 3 | P(x): 0.541 **(Round to three decimal places as needed.)** #### (b) Histogram Graph the probability distribution using a histogram. Choose the correct graph of the distribution below: - **Option A:** - Bars are at 0, 1, 2, and 3. - The heights are approximately 0.009, 0.171, 0.279, and 0.541 respectively. - **Option B:** - Bars are at 0, 1, 2, and 3. - The heights are different and don't match the calculated probabilities. - **Option C:** - Bars are at 0, 1, 2, and 3. - The heights decrease from 0 to 3, not matching the increasing values calculated. **Correct Answer: Option A** #### Histogram Shape Describe the histogram's shape. Choose the correct answer below: - **Skewed
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