A flat steel plate that weighs 1.0 N is resting on top of an aluminum ball which is resting on a flat steel plate. The properties of steel and aluminum are listed below. The diameter of the aluminum ball is 100 mm. Steel: Sy=600 MPa E₁=207*10° Pa Sy=276 MPa E₂= 100*10° Pa 12 211 Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using Maximum Shear Stress Theory? Aluminum: Steel d V1 = 292 AI Steel Z=0
A flat steel plate that weighs 1.0 N is resting on top of an aluminum ball which is resting on a flat steel plate. The properties of steel and aluminum are listed below. The diameter of the aluminum ball is 100 mm. Steel: Sy=600 MPa E₁=207*10° Pa Sy=276 MPa E₂= 100*10° Pa 12 211 Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using Maximum Shear Stress Theory? Aluminum: Steel d V1 = 292 AI Steel Z=0
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![Given
A flat steel plate that weighs 1.0 N is resting on top of an aluminum
ball which is resting on a flat steel plate. The properties of steel and
aluminum are listed below. The diameter of the aluminum ball is
100 mm.
Steel:
Aluminum:
Sy=600 MPa
E₁=207*10 Pa
Solution:
Sy=276 MPa
V₁ = 292
Steel
N=
d
TIITT
E₂= 100*10 Pa
v2 = 211
Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using
Maximum Shear Stress Theory?
Steel
-Z = O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e71aadb-37cc-405f-af5a-ab4863560ffa%2F74dc663a-011c-4d3b-a75b-d5c768a50951%2F69cnvcr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given
A flat steel plate that weighs 1.0 N is resting on top of an aluminum
ball which is resting on a flat steel plate. The properties of steel and
aluminum are listed below. The diameter of the aluminum ball is
100 mm.
Steel:
Aluminum:
Sy=600 MPa
E₁=207*10 Pa
Solution:
Sy=276 MPa
V₁ = 292
Steel
N=
d
TIITT
E₂= 100*10 Pa
v2 = 211
Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using
Maximum Shear Stress Theory?
Steel
-Z = O
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