GivenA flat steel plate that weighs 1.0 N is resting on top of an aluminumball which is resting on a flat steel plate. The properties of steel andaluminum are listed below. The diameter of the aluminum ball is100 mm.Steel:Aluminum:Sy=600 MPaE₁=207*10 PaSolution:Sy=276 MPaV₁ = 292SteelN=dTIITTE₂= 100*10 Pav2 = 211Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) usingMaximum Shear Stress Theory?Steel-Z = O

Solution: Given Data: *The weight of the steel plate, W=1 N *The diameter of the ball is, D = 100 mm…

A flat steel plate that weighs 1.0 N is resting on top of an aluminum ball which is resting on a flat steel plate. The properties of steel and aluminum are listed below. The diameter of the aluminum ball is 100 mm. Steel: Sy=600 MPa E₁=207*10° Pa Sy=276 MPa E₂= 100*10° Pa 12 211 Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using Maximum Shear Stress Theory? Aluminum: Steel d V1 = 292 AI Steel Z=0

A flat steel plate that weighs 1.0 N is resting on top of an aluminum ball which is resting on a flat steel plate. The properties of steel and aluminum are listed below. The diameter of the aluminum ball is 100 mm. Steel: Sy=600 MPa E₁=20710° Pa Sy=276 MPa E₂= 10010° Pa 12 211 Find: What is the factor of safety for the ball where the ball meets the flat surface (z= 0) using Maximum Shear Stress Theory? Aluminum: Steel d V1 = 292 AI Steel Z=0

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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