Engineering Econ HW4 Q3 A firm has installed a manufacturing line for packaging materials. The firm plans to produce 45tons of packing peanuts to sell at $4,000 per ton annually for 3 years, then 50 tons of packingpeanuts per year to sell at $4,250 per ton for the next 5 years. The firm uses a MARR of 8% peryear.a. What is the present worth of the expected income?b. The line is installed at a cost of $1 million in year 0. Given your answer in (a) as wellas this initial cost, is the manufacturing line a good investment, relative to the firm'sMARR? Why or why not?

Detailed explanation: Certainly! Let's break down the solution to the problem of evaluating the…

Answered: A firm has installed a manufacturing…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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A) Mary O’Leary’s company ships fine wool garments from CountyCork, Ireland. Five years ago she purchased some new automatedpacking equipment having a first cost of $125,000. The annual costsfor operating, maintenance, and insurance, as well as market valuedata for each year of the equipment’s 10-year useful life are asfollows. B) Now Mary is looking at the remaining 5 years of her investment inthis equipment. What is the marginal cost for each of the remaining5 years? When, if at all, should Mary replace this packing equipmentwith a new asset that has a minimum EUAC of $110,000?
Two machines are being considered for purchase. If the MARR (for this problem, also the minimum required interest rate) is 10%, which machine should be bought?
Hinson’s Homegrown Farms needs a new irrigation system. System one will cost $145,000, have annual maintenance costs of $10,000, and need an overhaul at the end of year six costing $30,000. System two will have first-year maintenance costs of $5000 with increases of $500 each year thereafter. System two would not require an overhaul. Both systems will have no salvage value after 12 years. If Hinson’s cost of capital is 4%, using annual worth analysis determine the maximum Hinson’s should be willing to pay for system two.
Engineering Economics Please provide a step by step solution using present worth method
A firm expects to install smog control equipment on the exhaust of a gasoline engine. The local smog control district has agreed to pay to the firm a lump sum of money to provide for the first cost of the equipment and maintenance during its 10-year useful life. At the end of 10 years the equipment, which initially cost $10,000, is valueless. The firm and the smog control district have agreed that the following are reasonable estimates of the end-of-year maintenance costs: Year 1 2 3 4 5 $75 100 125 150 175 Year 6 7 8 9 10 $200 225 250 275 300 Assuming interest at 6% per year, how much should the smog control district pay to the firm now to provide for the first cost of the equipment and its maintenance for 10 years?
please answer all with complete solution. do not use excel please. thank you...
A firm is considering which of twodevices to install to reduce costs. Both devices have useful lives of 5 years and no salvage value. Device A costs $10,000 and can be expected to result in $3000 savings annually. Device B costs $13,500 and will provide cost savings of $3000 the first year but will increase $500 annually, making the second-year savings $3500, the third-year savings $4000, and so forth. For a 7% MARR, which device should the firm purchase?
A machine Costs = $30000, O&M = $2000/year, Savings = $10000/year, Salvage @ 5 years = $7000. i = 10%. what is net present worth(after 5 years).
You are given the cash flow series for two projects, Alt. A and Alt. B. YEAR 1 2 3 4 5 6 Alt. A - F1 X X X + S1 Alt. B - F2 Y Y Y Y Y Y + S2 Assume that F2 > F1, and X, Y, S1, and S2 are positive; the incremental rate of return (i*) on the additional investment in Alt. B can be calculated with the following expression: = - = - = - · F2 + Y (P/A, i*, 6) + S2(P/F, i*, 6) (F2 F1) + (Y - X)(P/A, i*, 5) + (S2 - S1)(P/F, i*, 6) (F2 F1)(F/P, i*, 6) + (Y - X)(F/A, i*, 6) + (S2 - S1) (F2 F1)+(Y - X) + (Y + S2) - (X + S1) 0 = (F1 F2)(F/P, i*, 6) + (X - Y)(F/A, i*, 6) + (S2-S1) == 0 = F1 + X(P/A, i*, 6) + S1(P/F, i*, 6) 0F2+Y(P/A, i*, 6) + S2(P/F, i*, 6) 0 = - 0 = - F1 + X(P/A, i*, 5) + S1(P/F, i*, 6) F2+ Y(P/A, i*, 5) + S2(P/F, i*, 6)
Please no written by hand and no image
PLease answer this Asap and show which one is the right answer.
you can use excel or do it by hand, but please show how you got the answer

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