A dihybrid testcross is made to determine if genes C and D are linked. The results are shown in the table. 1. The chi-square value is the sum for all progeny classes of (observed-expected)2/expected. Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked. What is the chi-square value? 2. Using the chi-square test for goodness of fit, how many degrees of freedom are in this data set?

Human Anatomy & Physiology (11th Edition)
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Author:Elaine N. Marieb, Katja N. Hoehn
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Chapter1: The Human Body: An Orientation
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A dihybrid testcross is made to determine if genes C and D are linked. The results are shown in the table.

1. The chi-square value is the sum for all progeny classes of (observed-expected)2/expected. Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked. What is the chi-square value?

2. Using the chi-square test for goodness of fit, how many degrees of freedom are in this data set?

3. Using table 5.2 find the most accurate range within which the p value falls.

4. What is a reasonable conclusion based on the chi-square analysis?

 

TABLE 5.2 Critical Chi-Square Values
Values
0.99 0.90 0.50 0.10
0.05 0.01 0.001
Degrees of
Freedom
Values
1
0.02 0.45 2.71
3.84 6.64 10.83
0.02 0.21 1.39 4.61
5.99
9.21 13.82
3
0.11 0.58 2.37 6.25
7.81 11.35 16.27
4.
0.30 1.06 3.36 7.78
9.49 13.28 18.47
0.55 1.61
4.35 9.24
11.07
15.09 20.52
Transcribed Image Text:TABLE 5.2 Critical Chi-Square Values Values 0.99 0.90 0.50 0.10 0.05 0.01 0.001 Degrees of Freedom Values 1 0.02 0.45 2.71 3.84 6.64 10.83 0.02 0.21 1.39 4.61 5.99 9.21 13.82 3 0.11 0.58 2.37 6.25 7.81 11.35 16.27 4. 0.30 1.06 3.36 7.78 9.49 13.28 18.47 0.55 1.61 4.35 9.24 11.07 15.09 20.52
Parent genotypes:
Сс Dd x сс dd
Cc Dd
222
Cc dd
280
Progeny genotypes:
сc Dd
280
cc dd
218
1000
Transcribed Image Text:Parent genotypes: Сс Dd x сс dd Cc Dd 222 Cc dd 280 Progeny genotypes: сc Dd 280 cc dd 218 1000
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