Choose one 'group' results (for example you may choose group 4 from cross 2), complete the Chi-square Analysis with ONLY that group's data. Fill in the table below to help you determine the statistical significance of your chi-square. (you'll need to make multiple copies of this table, and may need to add more rows) Expected Cross Observed Expected (E) O-E (O-E)? (O-E)?/E (0) Ratio Sum of (O-E)?/E:

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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please help with chart 

 

Cross 2
3
5 6 total
Wild type 20 12 27 23
Ebory
Vestig al
Ebony Alesial
25
60 167
7
9 40
3
10
3 3
12 42
Transcribed Image Text:Cross 2 3 5 6 total Wild type 20 12 27 23 Ebory Vestig al Ebony Alesial 25 60 167 7 9 40 3 10 3 3 12 42
Choose one 'group' results (for example you may choose group 4 from cross 2),
complete the Chi-square Analysis with ONLY that group's data. Fill in the table below
to help you determine the statistical significance of your chi-square. (you'll need to
make multiple copies of this table, and may need to add more rows)
Expected
Observed
Expected
(E)
Cross
O-E
(0-E)?
(0-E)?/E
(0)
Ratio
Sum of (O-E)?/E:
Transcribed Image Text:Choose one 'group' results (for example you may choose group 4 from cross 2), complete the Chi-square Analysis with ONLY that group's data. Fill in the table below to help you determine the statistical significance of your chi-square. (you'll need to make multiple copies of this table, and may need to add more rows) Expected Observed Expected (E) Cross O-E (0-E)? (0-E)?/E (0) Ratio Sum of (O-E)?/E:
Expert Solution
Step 1

  Chi-square analysis is a simple test to determine if a hypothesis is true by quantifying the derivations expected by chance. The general convention is if the probability value is less than of 5%, the hypothesis is rejected. Chi square test was developed by Karl Pearson. It is the difference between observed and expected frequencies.

Characteristics of chi square test :

  • The null hypothesis refers that chance alone cannot account for the differences between observed and expected data because there are several other factors also which affects.
  • The null hypothesis refers that observed values are close enough to expected values.
  • The lower the overall chi square value the more likely the null hypothesis be accepted.
  • The higher the probability range associated with the overall chi square value ,the more likely null hypothesis will be rejected because if observed statistics is higher than critical value then null hypothesis will be rejected.
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