Full solution pls a) Define the term standard enthalpy change of neutralisation.b) The enthalpy change of reaction between NaHCO3 and HCI was determined experimentally.3.50 g of NaHCO3 (M, = 84.0) and 50 cm3 of 1.0 mol dm-3 HCI (aq) were mixed at time = 2 min,and several temperature readings were taken at fixed intervals. Fig. 1 shows the graph oftemperature against time.Using the information from the graph and assuming that the specific heat capacity and density ofall solutions are 4.18 J g-1 K-1 and 1.00 g cm-3 respectively, calculate the enthalpy change of thereaction:NaHCO3 (s) + HCI (aq) → NaCI (aq) + H2O (I) + CO2 (g)-State one assumption used in your calculation. 201816temperature / °C1412-101012time / minutesFig. 1c) The enthalpy change of neutralisation of HCl with NaOH is given to be -57.3 kJ mol-1.The following information is given:NaHCO3(s) + aq→ NaHCO3(aq); AH = +17.6 kJ mol-1By using these information and your answer to (b), construct an energy cycle and calculate AH.for the reaction:CO2(g) + NaOH(aq)→ NaHCO3(aq)d) A similar experiment carried out with hydrogen cyanide, HCN(aq), and aqueous ammonia gave avalue of -5.4 kJ mol-1 for the enthalpy change of neutralisation. The corresponding value forsodium hydroxide with hydrochioric acid was -57.0 kJ mol-1.Suggest a possible explanation for the difference in these two values.

Since you have asked multiple questions, we will solve the first question for you. If you want any…

a} Define the term standard enthalpy change of neutralisation. b) The enthalpy change of reaction between NaHCO3 and HCI was determined experimentally. 3.50 g of NaHCO3 (M, = 84.0) and 50 cm³ of 1.0 mol dm 3 HCI (aq) were mixed at time = 2 min, and several temperature readings were taken at fixed intervals. Fig. 1 shows the graph of temperature against time. Using the information from the graph and assuming that the specific heat capacity and density of all solutions are 4.18 J g1K-1 and 1.00 g cm-3 respectively, calculate the enthalpy change of the reaction: NaHCO3 (s) + HCI (aq) NaCI (aq) + H2O (1) + CO2 (g) State one assumption used in your calculation.

a} Define the term standard enthalpy change of neutralisation. b) The enthalpy change of reaction between NaHCO3 and HCI was determined experimentally. 3.50 g of NaHCO3 (M, = 84.0) and 50 cm³ of 1.0 mol dm 3 HCI (aq) were mixed at time = 2 min, and several temperature readings were taken at fixed intervals. Fig. 1 shows the graph of temperature against time. Using the information from the graph and assuming that the specific heat capacity and density of all solutions are 4.18 J g1K-1 and 1.00 g cm-3 respectively, calculate the enthalpy change of the reaction: NaHCO3 (s) + HCI (aq) NaCI (aq) + H2O (1) + CO2 (g) State one assumption used in your calculation.

Chemistry

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ISBN:9781305957404

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Chapter1: Chemical Foundations

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Full solution pls

a) Define the term standard enthalpy change of neutralisation.
b) The enthalpy change of reaction between NaHCO3 and HCI was determined experimentally.
3.50 g of NaHCO3 (M, = 84.0) and 50 cm3 of 1.0 mol dm-3 HCI (aq) were mixed at time = 2 min,
and several temperature readings were taken at fixed intervals. Fig. 1 shows the graph of
temperature against time.
Using the information from the graph and assuming that the specific heat capacity and density of
all solutions are 4.18 J g-1 K-1 and 1.00 g cm-3 respectively, calculate the enthalpy change of the
reaction:
NaHCO3 (s) + HCI (aq) → NaCI (aq) + H2O (I) + CO2 (g)
-
State one assumption used in your calculation.

20
18
16
temperature / °C
14
12-
10
10
12
time / minutes
Fig. 1
c) The enthalpy change of neutralisation of HCl with NaOH is given to be -57.3 kJ mol-1.
The following information is given:
NaHCO3(s) + aq→ NaHCO3(aq); AH = +17.6 kJ mol-1
By using these information and your answer to (b), construct an energy cycle and calculate AH.
for the reaction:
CO2(g) + NaOH(aq)
→ NaHCO3(aq)
d) A similar experiment carried out with hydrogen cyanide, HCN(aq), and aqueous ammonia gave a
value of -5.4 kJ mol-1 for the enthalpy change of neutralisation. The corresponding value for
sodium hydroxide with hydrochioric acid was -57.0 kJ mol-1.
Suggest a possible explanation for the difference in these two values.

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